Baumann's Cosmology (2)

Daniel Baumann  Cosmology  (Cambridge University Press 2022; version 3, April 2023)

Exercise solutions and some derivations (more Problems and solutions at Modern Cosmology Forum) by K S Kim



Part I The Homogeneous Universe

2 The Expanding Universe

The coarse-grained properties of the universe are remarkably simple. In particular, when averaged over large distances (larger than 100 Mpc) - the size of the observable universe is about 14,000 Mpc - the universe looks isotropic (the same in all directions). Assuming that we don't live at a special point in space - and that nobody else does either - the observed isotropy then implies that the universe is also homogeneous (the same at every point in space). This leads to a simple mathematical description of the universe because the spacetime geometry takes a very simple form.
   Observations of the light from distant galaxies have shown that the universe is expanding. Running this expansion backwards in time, we predict that nearly 14 billion years ago our whole universe was in a hot dense state. The Big Bang theory describes what happened in this fireball., and how it evolved into the universe we see today.

          2.1 Geometry 
Gravity is a manifestation of geometry of spacetime. To describe the evolution of our universe, we therefore stars by determining its spacetime geometry. This geometry is characterized by a spacetime metric. The large degree of symmetry of the homogeneous universe means that its metric will take a rather simple form

          2.1.1 Spacetime and Relativity
The metric is an object that turns coordinate distances into physical distances. In 3-dimensional Euclidean space, the physical distance between two points separated by the infinitesimal coordinate distances 𝑑𝑥, 𝑑𝑦 and 𝑑𝑧
    (2.1)   𝑑𝓁2 = 𝑑𝑥2 + 𝑑𝑦2 + 𝑑𝑧2 = ∑3𝑖,𝑗=1 𝛿𝑖𝑗𝑑𝑥𝑖𝑑𝑥𝑗,     where (𝑥1, 𝑥2, 𝑥3) = (𝑥, 𝑦, 𝑧).  
Here the metric is simply the Kronecker delta 𝛿𝑖𝑗 = diag(1, 1, 1). If we use polar coordinate,
    (2.2)   𝑑𝓁2 = 𝑑𝑟2 + 𝑟2𝑑𝜃2 + 𝑟2sin2(𝜃)𝑑𝜙2 ≡ ∑3𝑖,𝑗=1 𝑔𝑖𝑗 𝑑𝑥𝑖𝑑𝑥𝑗     where (𝑥1, 𝑥2, 𝑥3) = (𝑟, 𝜃, 𝜙).
Here the metric is, a less trivial form, 𝑔𝑖𝑗 = diag(1, 𝑟2, 𝑟2sin2𝜃). Observers can use different coordinate systems will always agree on the physical distance, 𝑑𝑙 which is an invariant. Hence, the metric turns observer-dependent coordinates into invariants.    A fundamental object in relativity is the spacetime metric. It turns observer-dependent spacetime coordinates 𝑥𝜇 = (𝑐𝑡, 𝑥𝑖)  into the invariant line element1
    (2.3)   𝑑𝑠2 = ∑3𝜇,𝜈=0 𝑔𝜇𝜈𝑑𝑥𝜇𝑑𝑥𝜈 ≡ 𝑔𝜇𝜈𝑑𝑥𝜇𝑑𝑥𝜈.    [𝑥0 ≡ 𝑐𝑡 and 𝑥𝑖, 𝑖 = 1, 2, 3]
In special relativity, the spacetime is Minkowski space, 𝙍1,3, whose line element is
    (2.4)   𝑑𝑠2 = -𝑐2𝑑𝑡 2 + 𝛿𝑖𝑗 𝑑𝑥𝑖𝑑𝑥𝑗,
so that the metric is simply 𝑔𝜇𝜈 = diag(-1, 1, 1, 1). An important feature of this metric is that the associated spacetime curvature vanishes. In general relativity, on the other hand, the metric depend on the position in spacetime, 𝑔𝜇𝜈(𝑡, 𝐱), in such a way that the spacetime curvature is nontrivial. This spacetime dependence of the metric incorporates the effects of gravity. How the metric varies throughout spacetime is determined by the distribution of matter and energy in the universe.
Indices  From special relativity the metric is used to raise and lower indices on 4-vectors (and on general tensors),
    (2.5)   𝐴𝜇 = 𝑔𝜇𝜈𝐴𝜈   and     𝐴𝜇 = 𝑔𝜇𝜈𝐴𝜈,
where 𝑔𝜇𝜈 is the inverse metric defined by [𝑔𝜇𝜈 [Wikipedia Invertible matrix: 𝐀𝐁 = 𝐁𝐀 = 𝐈𝑛 where 𝐈𝑛 denotes 𝑛-by-𝑛 identity matrix.]
    (2.6)   𝑔𝜇𝜆𝑔𝜆𝜈 = 𝛿𝜇𝜈 = {1   𝜇 = 𝜈,     0   𝜇 ≠ 𝜈.
4-vectors with a lower index, 𝐴𝜇, are sometimes called covariant to distinguish them from the contravariant 4-vectors, 𝐴𝜇, with an upper index. Covariant and contravariant vectors can be contracted to produce an invariant scalar,
    (2.7)   𝑆 ≡ 𝐴 ⋅ 𝐵 = 𝐴𝜇𝐵𝜇 = 𝑔𝜇𝜈𝐴𝜇𝐵𝜇.
   The spatial homogeneity and isotropy of the universe mean that it can be represented by a time-ordered sequence of 3-dimensional spatial slices, each of which is homogeneous and isotropic (see Fig. 2.1). The 4-dimensional element can then be written as2
    (2.8)   𝑑𝑠2 = -𝑐2𝑑𝑡2 + 𝑎2(𝑡)𝑑𝓁2,
where 𝑑𝓁2 ≡ 𝛾𝑖𝑗(𝑥𝑘)𝑑𝑥𝑖𝑑𝑥𝑗 is the line element on the spatial slices and 𝑎(𝑡) is the scale factor, which describes the expansion of the universe. [Wikipedia Scale factor: In expanding or contracting universe, 𝑑(𝑡) = 𝑎(𝑡)𝑑0, where 𝑑(𝑡) is the proper distance at time 𝑡, 𝑑0 is the distance at the reference time 𝑡0,𝑑(𝑡0), usually also referred to as comoving distance, and 𝑎(𝑡) is the scale factor. Thus, by definition, 𝑎(𝑡0) = 1]

          2.1.2 Symmetric Three-spaces 
Homogeneous and isotropic 3-spaces must have constant intrinsic curvature.Then the curvature can be zero, positive or negative.

Flat space: The simplest possibility is 3-dimensional Euclidean space 𝐸3. This is the space in which parallel lines don't intersect. Its line element is
    (2.9)   𝑑𝓁2 = 𝑑𝐱2 = 𝛿𝑖𝑗𝑑𝑥𝑖𝑑𝑥𝑗,
which is clearly invariant under spatial translations 𝑥𝑖 ↦ 𝑥𝑖 + 𝑎𝑖 and rotations 𝑥𝑖 ↦ 𝑅𝑖𝑘𝑥𝑘, with 𝛿𝑖𝑗𝑅𝑖𝑘𝑅𝑗𝑙 = 𝛿𝑘𝑙.

Spherical space: The next possibility is a 3-space with constant positive curvature. On such a space, parallel lines will eventually meet. This geometry can be represented as a 3-sphere 𝑆3 embedded in 4-dimensional Euclidean space 𝐸4:
    (2.10)   𝑑𝓁2 = 𝑑𝐱2 + 𝑑𝑢2,     𝐱2 + 𝑢2 = 𝑅02, where 𝑅0 is the radius of the sphere. Homogeneity and isotropy on the surface of the 3-sphere are inherited from the symmetry of the line element under 4-dimensional rotations.  

Hyperbolic space: We can have a 3-space with constant negative curvature. On such a space parallel lines diverge. This geometry can be represented as a hyperboloid 𝐻3 embedded in 4-dimensional Lorentzian space 𝙍1,3:
    (2.11)   𝑑𝓁2 = 𝑑𝐱2 - 𝑑𝑢2,     𝐱2 - 𝑢2 = -𝑅02,
where 𝑅02 > 0 is a constant determining the curvature of the hyperboloid. Homogeneity and isotropy of the induced geometry on the hyperboloid are inherited from the symmetry of the line element under 4-dimensional pseudo-rotations - i.e. Lorentz transformations, with 𝑢 playing the role of time.

The line elements of the spherical and hyperbolic cases can be combined as
    (2.12)   𝑑𝓁2 = 𝑑𝐱2 ± 𝑑𝑢2,     𝐱2 ± 𝑢2 = ±𝑅02.
The differential of the embedding condition gives 𝑢𝑑𝑢 = ∓𝐱 ⋅ 𝑑𝐱, so that we can eliminate the dependence on the auxiliary coordinate 𝑢 from the line element [𝑑𝑢2/𝑑𝑢 = 𝑑(𝑅02 -  𝐱2)/𝑑𝐱 𝑑𝐱/𝑑𝑢, 𝑢𝑑𝑢 = -𝐱 𝑑𝐱, 𝑑𝑢2 = -(𝐱 𝑑𝐱)2/𝑢2]
    (2.13)   𝑑𝓁2 = 𝑑𝐱2 ± (𝐱 ⋅ 𝑑𝐱)2/(𝑅02 ∓ 𝐱2).    
Finally, we can unify (2.13) with (2.9) by writing
    (2.14)   𝑑𝓁2 = 𝑑𝐱2 + 𝑘 (𝐱 ⋅ 𝑑𝐱)2/(𝑅02 - 𝑘 𝐱2),    for   𝑘 ≡ {0   𝐸3,     +1   𝑆3,     -1   𝐻3.
To make the symmetries of the space more manifest, it is convenient to write the metric in spherical polar coordinates, (𝑟, 𝜃, 𝜙). Using
    (2.15)   𝑑𝐱2 = 𝑑𝑟2+ 𝑟2(𝑑𝜃2 + sin2(𝜃)𝑑𝜙),     𝐱 ⋅ 𝑑𝐱 = 𝑟𝑑𝑟,      𝐱2 = 𝑟2,
the metric in (2.14) becomes
    (2.16)   𝑑𝓁2 = 𝑑𝑟2/(1 - 𝑘𝑟2/𝑅02) + 𝑟2𝑑𝛺2,
where 𝑑𝛺2 ≡ 𝑑𝜃2 + sin2(𝜃)𝑑𝜙 is the metric on the unit 2-spheres.  

         2.1.3 Robertson-Walker Metric
Substituting (2.16) into (2.8), we obtain the Robertson-Walker metric in polar coordinates:
    (2.17)   𝑑𝑠2 = -𝑐2𝑑𝑡2 + 𝑎2(𝑡)[𝑑𝑟2/(1 - 𝑘𝑟2/𝑅02) + 𝑟2𝑑𝛺2],
which is sometimes also called the Friedmann-Robertson-Walker (FRW) metric. [Wikipedia Friedmann-Lemaȋtre-Robertson-Walker metric: in short FLRW or FRW etc.] Notice that the symmetries of the universe have reduced the ten independent components of the spacetime metric 𝑔𝜇𝜈 to a single function of time, the scale factor 𝑎(𝑡), and a constant, the curvature scale 𝑅0.

First of all, the line element (2.17) has a rescaling symmetry
    (2.18)   𝑎 → 𝜆𝑎,    𝑟 → 𝑟/𝜆,     𝑅0 → 𝑅0/𝜆
this means that the geometry of the spacetime stays same if we simultaneously rescale  𝑎, 𝑟 and 𝑅0 by a constant 𝜆 as in (2.18). We can use this freedom to set the scale factor today, at  𝑡 = 𝑡0, to be unity, 𝑎(𝑡0) ≡ 1. The scale 𝑅0 is then the physical curvature scale today, justifying the use of the subscript.

The coordinate 𝑟 is called a comoving coordinate, which can be changed using the rescaling in (2.18) and hence is not a physical observable. Physical results can only depend on the physical coordinate,  𝑟phys = 𝑎(𝑡)𝑟 (see Fig. 2.2)
   Consider a galaxy with a trajectory 𝐫(𝑡) in comoving coordinates and 𝐫phys = 𝑎(𝑡)𝐫 in physical coordinates. The physical velocity of the galaxy
is     (2.19)   𝐯phys ≡ 𝑑𝐫phys/𝑑𝑡 = 𝑑𝑎/𝑑𝑡 𝐫 + 𝑎(𝑡) 𝑑𝐫/𝑑𝑡 = 𝐻𝐫phys + 𝐯pec,
where we have introduced the Hubble parameter
    (2.20)   𝐻 ≡ 𝑎̇/𝑎.
Here ȧ = 𝑑𝑎/𝑑𝑡. We see that in (2.19) the first term 𝐻𝐫phys is the Hubble flow, which is the velocity of the galaxy resulting from the expansion of space between the origin and 𝐫phys(𝑡). the second term 𝐯pec ≡ 𝑎(𝑡) , is the peculiar velocity, which is the velocity measured by a "comoving observer" (i.e. an observer who follows the Hubble flow). It describes the motion of galaxy relative to the cosmological rest frame, typically due to the gravitational attraction of other nearby galaxies.

The complicate 𝑔𝑟𝑟 component of (2.17) may sometimes be redefined, 𝑑𝜒 ≡ 𝑑𝑟/√(1 - 𝑘𝑟2/𝑅02), then
    (2.21)   𝑑𝑠2 = -𝑐2𝑑𝑡2 + 𝑎2(𝑡)[𝑑𝜒2 + 𝑆𝑘2(𝜒)𝑑𝛺2],
where
    (2.22)   𝑆𝑘(𝜒) = 𝑅0 {sinh(𝜒/𝑅0)  𝑘 = -1,     𝜒/𝑅0   𝑘 = 0,     sin(𝜒/𝑅0)   𝑘 = +1.
Note that for for 𝑘 = 0 there is no distinction between 𝑟 and 𝜒. The form of metric in (2.21) will be useful when we define observable distances in section 2.2.3.

Finally, it is often helpful to introduce conformal time, 𝜂
    (2.23)   𝑑𝜂 = 𝑑𝑡/
so that (2.21) becomes
    (2.24)   𝑑𝑠2 = 𝑎2(𝜂)[-𝑐2𝑑𝜂2 + [𝑑𝜒2 + 𝑆𝑘2(𝜒)𝑑𝛺2].  
We see that the metric has now factorized into a static part and a time-dependent conformal factor 𝑎(𝜂). This is convenient for studying the propagation of light, for which 𝑑𝑠2 = 0. As we will see in section 2.3.6, going to conformal time also will be useful change of variables for certain exact solutions to the Einstein equations.

          2.2 Kinematics   
  Having found the metric of the expanding universe, we now want to determine how particles evolve in the spacetime. It is an essential feature of general relativity that freely falling particles in a curved spacetime moving along geodesics. Some basic facts about geodesic motion in GR will be introduced and then it be applied to FRW spacetime. [RE Appendix A for more detail]

          2.2.1 Geodesics Let us first look at simpler problem of a free particle in 2-dimensional Euclidean space.

          Curvilinear coordinates
In the absence of any forces, Newton's law simply reads 𝑑2𝐱/𝑑𝑡2 = 0 [ = 0], which in Cartesian coordinates 𝑥𝑖 = (𝑥, 𝑦) becomes
    (2.25)   𝑑2𝑥𝑖/𝑑𝑡2 = 0.
In a general coordinate system, however, = 0 does not have to imply 𝑑2𝑥𝑖/𝑑𝑡2 = 0. For example in the polar coordinate (𝑟, 𝜙), using 𝑥 = 𝑟 cos(𝜙) and 𝑦 = 𝑟 sin(𝜙), the equation of motion in (2.25) imply
    (2.26)   0 = ẍ = 𝑑𝑟̇/𝑑𝑡 cos(𝜙) - 2 sin(𝜙)𝑟̇𝜙̇ - 𝑟 cos(𝜙)𝜙̇2 - 𝑟 sin(𝜙) 𝑑𝜙̇/𝑑𝑡,  
                     0 = ÿ = 𝑑𝑟̇/𝑑𝑡 sin(𝜙) + 2 cos (ϕ)𝑟̇𝜙̇ - 𝑟 sin(ϕ)𝜙̇2 + 𝑟 cos(ϕ) 𝑑𝜙̇/𝑑𝑡.
Solving this for 𝑑ṙ/𝑑𝑡 and 𝑑𝜙̇/𝑑𝑡, we find
    (2.27)   𝑑𝑟̇/𝑑𝑡 = 𝑟𝜙̇2,     𝑑𝜙̇/𝑑𝑡 = - 2/𝑟 ṙ𝜙̇.
we see that 𝑑𝑟̇/𝑑𝑡 ≠ 0 and 𝑑𝜙̇/𝑑𝑡 ≠ 0. The reason is simply that in polar coordinates the basis vector 𝐫̂ and 𝝓̂ vary in the plane. To keep = 0, the coordinates must then satisfy (2.27).

Exercise 2.1   Show that the equations (2.27) can also be derive the Lagrangian of the free particle
    (2.28)   𝐿 = 𝑚/2 (𝑟̇2 + 𝑟2𝜙̇2),
   where 𝑚 is the mass of the particle.
[Solution]   Using Euler-Lagrange equation for the coordinate 𝑟 is
   (a)   𝑑/𝑑𝑡 (∂𝐿/∂𝑟̇) = ∂𝐿/∂𝑟   ⇒   (∂𝐿/∂𝑟̇) = 𝑑/𝑑𝑡 [𝑚/2 (2𝑟̇ + 0)] = 𝑚 𝑑𝑟̇/𝑑𝑡, ∂𝐿/∂𝑟 = 𝑚/2 (0 + 2 𝑟𝜙̇2) = 𝑚𝑟𝜙̇2.   ⇒   𝑑𝑟̇/𝑑𝑡 = 𝑟𝜙̇2.
Similarly, for the coordinate 𝜙, we get 
   (b)   𝑑/𝑑𝑡 (∂𝐿/∂𝜙̇) = ∂𝐿/∂𝜙   ⇒   𝑑/𝑑𝑡 (∂𝐿/∂𝜙̇) = 𝑑/𝑑𝑡 [𝑚/2 (0 + 2 𝑟2𝜙̇)] = 𝑚 𝑑/𝑑𝑡 𝑟2𝜙̇ = 𝑚 (𝑑𝑟2/𝑑𝑡 𝜙̇ + 𝑟2 𝑑𝜙̇/𝑑𝑡) = 𝑚 (2𝑟𝑟̇𝜙̇ + 𝑟2 𝑑𝜙̇/𝑑𝑡),
         ∂𝐿/∂ϕ = 𝑚/2 (0 + 0) = 0, 2𝑟𝑟̇𝜙̇ + 𝑟2 𝑑𝜙̇/𝑑𝑡 = 0.   ⇒   𝑑𝜙̇/𝑑𝑡 = -2/𝑟 𝑟̇𝜙̇. ▮

   To derive the equation of motion in an arbitrary coordinate system, which metric 𝑔𝑖𝑗 ≠ 𝛿𝑖𝑗, we start from the Lagrangian
    (2.29)   𝐿 = 𝑚/2 𝑔𝑖𝑗(𝑥𝑘) ẋ𝑖𝑗.
Substituting this into the Euler-Lagrangian equation, we find
    (2.30)   𝑑2𝑥𝑖/𝑑𝑡2 = -𝛤𝑖𝑎𝑏 𝑑𝑥𝑎/𝑑𝑡 𝑑𝑥𝑏/𝑑𝑡,
where we have introduced the Christoffel symbol
    (2.31)   𝛤𝑖𝑎𝑏 ≡ 1/2 𝑔𝑖𝑗(∂𝑎𝑔𝑗𝑏 + ∂𝑏𝑔𝑗𝑎 - ∂𝑗𝑔𝑎𝑏),     with   ∂𝑗 ≡ ∂/∂𝑥𝑗.
Derivation   The Euler-Lagrangian equation is
    (2.32)   𝑑/𝑑𝑡 (∂𝐿/∂ẋ𝑘) = ∂𝐿/∂𝑥𝑘.
The mass 𝑚 will be cancel on both side. The left-hand side of (2.32) then becomes [∂𝐿/∂ẋ𝑘 = 1/2 ∂(𝑔𝑖𝑗𝑖𝑗)/∂ẋ𝑘 = 1/2 (𝑔𝑖𝑘𝑖 + 𝑔𝑘𝑗𝑗) = 𝑔𝑖𝑘𝑖]
    (2.33)   𝑑/𝑑𝑡 (∂𝐿/∂ẋ𝑘) = 𝑑/𝑑𝑡 (𝑔𝑖𝑘𝑖) = 𝑔𝑖𝑘𝑖 + 𝑑𝑥𝑗/𝑑𝑡 ∂𝑔𝑖𝑘/∂𝑥𝑗𝑖 = 𝑔𝑖𝑘𝑖 + ∂𝑗𝑔𝑖𝑘𝑖𝑗 = 𝑔𝑖𝑘𝑖 + 1/2 (∂𝑖𝑔𝑗𝑘 + ∂𝑗𝑔𝑖𝑘) ẋ𝑖𝑗,
while the right-hand side is
    (2.34)   ∂𝐿/∂𝑥𝑘 = 1/2 ∂𝑘𝑔𝑖𝑗𝑖𝑗. Combing (2.33) and (2.34) then gives     (2.35)   𝑔𝑖𝑘𝑖 = -1/2 (∂𝑖𝑔𝑗𝑘 + ∂𝑗𝑔𝑖𝑘 - ∂𝑘𝑔𝑖𝑗) ẋ𝑖𝑗
Multiplying both sides by 𝑔𝑙𝑘, and using 𝑔𝑙𝑘 𝑔𝑘𝑖 = 𝛿𝑙𝑖, we get     (2.36)   ẍ𝑙 = -1/2 𝑔𝑙𝑘(∂𝑖𝑔𝑗𝑘 + ∂𝑗𝑔𝑖𝑘 - ∂𝑘𝑔𝑖𝑗) ẋ𝑖𝑗 ≡ -𝛤𝑙𝑖𝑗,
which is the desired result (2.30). ▮
   The equation of motion of a massive particle in general relativity will take a similar form as (2.30). However, i this case, the term involving the Christoffel symbol cannot be removed by going to Cartesian coordinate, but is a physical manifestation of the spacetime curvature.

          Curved spacetime
For massive particles, a geodesic is the timelike curve 𝑥𝜇(𝜏) which extremises the proper time 𝛥𝜏 between two points in the spacetime.3 This extremal path satisfies the following geodesic equation
    (2.37)   𝑑2𝑥𝜇/𝑑𝜏2 = -𝛤𝑖𝑎𝑏 𝑑𝑥𝑎/𝑑𝜏 𝑑𝑥𝑏/𝑑𝜏,  
where the Christoffel symbol is
    (2.38)   𝛤𝜇𝛼𝛽 = 1/2 𝑔𝜇𝜆(∂𝛼𝑔𝛽𝜆 + ∂𝛽𝑔𝛼𝜆 - ∂𝜆𝑔𝛼𝛽),     with   ∂𝛼 ≡ ∂/∂𝑥𝛼.
Notice the similarity between (2.37) and (2.30).
   It will be convenient to write the geodesic equation in terms of the 4-momentum of the particle
    (2.39)   𝛲𝜇 ≡ 𝑚 𝑑𝑥𝜇/𝑑𝜏. 
Using the chain rule, we have     (2.40)    𝑑/𝑑𝜏 𝛲𝜇(𝑥𝛼(𝜏)) = 𝑑𝑥𝛼/𝑑𝜏 ∂𝛲𝜇/∂𝑥𝛼 = 𝛲𝛼/𝑚 ∂𝛲𝜇/∂𝑥𝛼,  
   so that (2.37) becomes
    (2.41)   [𝑚2 𝑑2𝑥𝜇/𝑑𝜏2 =] 𝛲𝛼 ∂𝛲𝜇/∂𝑥𝛼 = -𝛤𝜇𝛼𝛽 𝛲𝛼𝛲𝛽.
Rearranging the expression, we can also write
    (2.42)   𝛲𝛼(∂𝛼𝛲𝛼 + 𝛤𝜇𝛼𝛽𝛲𝛽) = 0.
The term in brackets is so-called covariant derivative of 4-vector 𝛲𝜇 which we denote by ∇𝛼𝛲𝜇 ≡ ∂𝛼𝛲𝛼 + 𝛤𝜇𝛼𝛽𝛲𝛽. So we can write:
    (2.43)   𝛲𝛼𝛼𝛲𝜇 = 0.
   The form of the geodesic equation in (2.43) is particularly convenient because it also applies to massless particles.If we interpret 𝛲𝜇 ≡ 𝑚 𝑑𝑥𝜇/𝑑𝜆 as the 4-momentum of a massless particle, where 𝜆 now parameterizes the curve 𝑥𝜇(𝜆). Accepting that the geodesic equation (2.43) is valid  for both massive and massless particles, we will apply it to particles in the FRW spacetime.

          Free particles in FRW
To evaluate the right-hand side of (2.41), we need the Christoffel symbols for the for the FRW metric,
    (2.44)   𝑑𝑠2 = -𝑐2𝑑𝑡2 + 𝑎2(𝑡) 𝛾𝑖𝑗 𝑑𝑥𝑗𝑑𝑥𝑖
where the form of the spatial metric 𝛾𝑖𝑗 depends on our choice of spatial  coordinates and on the curvature of the spatial slices. Substituting 𝑔𝜇𝜈 = diag(-1, 𝑎2(𝑡) 𝛾𝑖𝑗) into the definition (2.38), it is straightforward to compute the Christoffel symbols. Note that all Christoffel symbols with two time[-0] indices vanish, i.e. 𝛤𝜇00 = 𝛤00𝛽 and 𝛤𝜇𝛼𝛽 = 𝛤𝜇𝛽𝛼. The only nonzero components are
    (2.45)   𝛤0𝑖𝑗 = 𝑐-1𝑎ȧ𝛾𝑖𝑗,    𝛤𝑖0𝑗 = 𝑐-1ȧ/𝑎𝛿𝑖𝑗,     𝛤𝑖𝑗𝑘 = 1/2 𝛾𝑖𝑙(∂𝑗𝛾𝑘𝑙 + ∂𝑘𝛾𝑗𝑙 - ∂𝑙𝛾𝑗𝑘).

Example   Let us derive 𝛤0𝛼𝛽 for metric (2.44).
    (2.46)   𝛤0𝛼𝛽 = 1/2 𝑔0𝜆(∂𝛼𝑔𝛽𝜆 + ∂𝛽𝑔𝛼𝜆 - ∂𝜆𝑔𝛼𝛽).
The factor 𝑔0𝜆 vanish unless 𝜆 = 0, 𝑔00 = -1. Hence we have
    (2.47)   𝛤0𝛼𝛽 = -1/2 (∂𝛼𝑔𝛽0 + ∂𝛽𝑔𝛼0 - ∂0𝑔𝛼𝛽).
The first two terms reduced to derivatives of 𝑔00 and 𝑔00 = -1, so we have
    (2.48)   𝛤0𝛼𝛽 = 1/2 ∂0𝑔𝛼𝛽.
0 means ∂/∂𝑥0 and 𝑥0 ≡ 𝑐𝑡 so ∂0 = 𝑐-1𝑡. The derivative is nonzero if 𝑔𝑖𝑗 = 𝑎2𝛾𝑖𝑗. In that case we find
    (2.49)   𝛤0𝛼𝛽 = 1/2 𝑐-1∂/∂𝑡 𝑎2𝛾𝑖𝑗 = 1/2 𝑐-1∂/∂𝑎 𝑎2𝛾𝑖𝑗 ∂𝑎/∂𝑡 = 𝑐-1𝑎ȧ𝛾𝑖𝑗. ▮

Exercise 2.2   Derive 𝛤𝑖0𝑗 and 𝛤𝑖𝑗𝑘 for metric (2.44).
[Solution]   From the definition of the Christoffel symbol, we have
   (a)   𝛤𝑖0𝑗 = 1/2 𝑔𝑖𝜆(∂0𝑔𝑗𝜆 + ∂𝑗𝑔0𝜆 - ∂𝜆𝑔0𝑗),   But 𝑔0𝑗 = 𝑔0𝜆 = 0, this becomes 
   (b)   𝛤𝑖0𝑗 = 1/2 𝑔𝑖𝜆0𝑔𝑗𝜆, 𝑔𝑖𝜆 = 1/𝑎2 𝛾𝑖𝜆. And since ∂0 = 𝑐-1𝑡 and 𝑔𝑗𝜆 = 𝑎2𝛾𝑗𝜆, ∂0𝑔𝑗𝜆 = 𝑐-1 2𝑎𝑎̇𝛾𝑖𝜆.
  ⇒   𝛤𝑖0𝑗 = 1/2 1/𝑎2 𝛾𝑖𝜆 𝑐-1 2𝑎𝑎̇𝛾𝑖𝜆 = 𝑐-1 𝑎̇/𝑎 𝛿𝑖𝑗.
Similarly, we have
   (c)   𝛤𝑖𝑗𝑘 = 1/2 𝑔𝑖𝑙(∂𝑗𝑔𝑘𝑙 + ∂𝑘𝑔𝑗𝑙 - ∂𝑙𝑔𝑗𝑘), Since 𝑔𝑖𝑙 = 1/𝑎2 𝛾𝑖𝑙 and the derivative is nonzero, if 𝑗, 𝑘 and 𝑙 are spatial indices, 𝑔𝑗𝑙 = 𝑎2 𝛾𝑗𝑙, 𝑔𝑘𝑙 = 𝑎2 𝛾𝑘𝑙 and 𝑔𝑗𝑘 = 𝑎2 𝛾𝑗𝑘 respectively.   ⇒   𝛤𝑖𝑗𝑘 = 1/2 1/𝑎2 𝛾𝑖𝑙(∂𝑗 𝑎2 𝛾𝑘𝑙 + ∂𝑘 𝑎2 𝛾𝑗𝑙 - ∂𝑙 𝑎2 𝛾𝑗𝑘) = 1/2 𝛾𝑖𝑙(∂𝑗 𝛾𝑘𝑙 + ∂𝑘 𝛾𝑗𝑙 - ∂𝑙 𝛾𝑗𝑘). ▮

   The case of massless particle (like photons) will be specialized. The left-hand side of (2.41) can be written when 𝛼 = 0
    (2.50)   𝛲0 ∂𝛲𝜇/∂𝑥0 = 𝛲0/𝑐 𝑑𝛲𝜇/𝑑𝑡, [Notice that 𝑥0 ≡ 𝑐𝑡 and ∂0 = 𝑐-1𝑡.]
    (2.51)   𝛲0/𝑐 𝑑𝛲𝜇/𝑑𝑡 = -𝛤𝜇𝛼𝛽 𝛲𝛼𝛲𝛽.
Let us consider the 𝜇 = 0 component of the equation, Then the right term is -𝛤0𝑖𝑗 𝛲𝑖𝛲𝑗. Using 𝛲0 = 𝐸/𝑐 and 𝛤0𝑖𝑗 = 𝑐-1𝑎𝑎̇𝛾𝑖𝑗 then we find,
    (2.52)   𝐸/𝑐3 𝑑𝐸/𝑑𝑡 = -𝑐-1𝑎𝑎̇𝛾𝑖𝑗𝛲𝑖𝛲𝑗.
For massless particles, the 4-momentum 𝛲𝜇 = (𝐸/𝑐, 𝛲𝑖) obey the constraint
    (2.53)   𝑔𝜇𝜈𝛲𝑖𝛲𝜈 = -𝑐2𝐸2 + 𝑎2𝛾𝑖𝑗𝛲𝑖𝛲𝑗 = 0.    [Notice that lightlike 𝑑𝑠2 = 0.]
This allow us to write (2.51) as
    (2.54)   1/𝐸 𝑑𝐸/𝑑𝑡 = -𝑎̇/𝑎,     [ (1/𝐸 𝑑𝐸/𝑑𝑡) 𝑑𝑡 = log(𝐸) + const; (-1/𝑎 𝑑𝑎/𝑑𝑡) 𝑑𝑡 = log(𝑎-1) + const   ⇒   𝐸 ∝𝑎-1]
which implies that the energy of a massless particle decays with the expansion of the universe, 𝐸 ∝𝑎-1.

Exercise 2.3   Repeating the analysis for massive particle, with
    (2.55)   𝑔𝜇𝜈𝑃𝜇𝑃𝜈 = -𝑚2𝑐2
   show that the physical 3-momentum, defined as 𝑝2 ≡ 𝑔𝑖𝑗𝑃𝑖𝑃𝑗, satisfies 𝑝 ∝𝑎-1. Show that the momentum can be written as
    (2.56)   𝑝 = 𝑚𝑣/√(1 - 𝑣2/𝑐2).
   where 𝑣2 ≡ 𝑔𝑖𝑗𝑖𝑗 is the physical peculiar velocity. Since 𝑝 ∝𝑎-1, freely falling particles will therefore converge onto the Hubble flow.
[Solution]   In the text, we have shown that the geodesic equation of a particle with 4-momentum 𝑃𝜇 = (𝐸/𝑐, 𝑃𝑖) can be written as
   (a)   𝐸/𝑐3 𝑑𝐸/𝑑𝑡 = -𝑐-1 𝑎̇/𝑎 𝑝2,
   (b)   𝑔𝜇𝜈𝑃𝜇𝑃𝜈 = -𝑐-2𝐸2 + 𝑝2 = -𝑚2𝑐2   [Take a time derivative the both side of the equation and arrange them.]
   (c)   𝐸/𝑐3 𝑑𝐸/𝑑𝑡 = 𝑝/𝑐 𝑑𝑝/𝑑𝑡 = -𝑐-1 𝑎̇/𝑎 𝑝2,
   (d)   ṗ/𝑝 = -ȧ/𝑎.
The physical 3-momentum of a massive particle therefore decreases as 𝑝 ∝𝑎-1.
   From the definition of 4-momentum of a massive particle, we get
   (e)   𝑃𝑖 ≡ 𝑚 𝑑𝑥𝑖/𝑑𝜏 = 𝑚 𝑑𝑥/𝑑𝜏 ẋ𝑖 = 𝑚ẋ𝑖/√(1 - 𝑔𝑖𝑗𝑖𝑗/𝑐2) = 𝑚ẋ𝑖/√(1 - 𝑣2/𝑐2)    
    Now we have (2.56), 𝑝 = 𝑚𝑣/√(1 - 𝑣2/𝑐2).
Since 𝑝 decreases with the expansion of the universe, so will 𝑣, showing that freely falling particles will converge onto the Hubble flow. ▮

          2.2.2 Redshift
The light emitted by a distant galaxy can be interpreted either quantum mechanically as freely-propagating photons or classically as propagating electromagnetic waves. To analyze the observation correctly, we need to take into account that wavelength of light gets stretched (or equivalently, the photons lose energy) by the expansion of the universe.
   Recall wavelength 𝜆 = 𝘩/𝛦, where 𝛦 is photon energy and 𝘩 is Planck's constant. Since the energy of photon evolves as 𝐸 ∝𝑎-1, the wavelength scales as 𝜆 ∝𝑎. Light emitted at a time 𝑡1 with 𝜆1 will be observed at a later time 𝑡0 with a larger wavelength
    (2.57)   𝜆1 = 𝑎(𝑡0)/𝑎(𝑡1) 𝜆0.
This increased wavelength is called redshift, since red light has a longer wavelength than blue light.
   The same result can be derived by the classical method. Consider a galaxy at a fixed comoving distance 𝑑. Since the spacetime is isotropic, we can choose coordinates for which light travels in the radial direction with 𝜃 = 𝜙 =const. Then the evolution is determined by a 2-dimensional line element.
    (2.58)   𝑑𝑠2 = 𝑎2(𝜂)[-𝑐2𝑑𝜂2 + 𝑑𝜒2].
Since photons travel along null geodesics, with 𝑑𝑠2 = 0, their path is
    (2.59)   ∆𝜒(𝜂) = ±𝑐𝛥𝜂,
where the plus sign corresponds to outgoing photons and its minus sign to incoming photons. This shows the main benefit of working with conformal time: light rays correspond to straight lines in the 𝜒-𝜂 coordinates. Moreover comoving distance to a source is simply equal to the difference in conformal time between the moments of being emitted and received.
   At a time 𝜂1, the galaxy emits a signal of a short conformal duration 𝛿𝜂 (see Fig. 2.3).The light arrives at our telescopes at time 𝜂0 = 𝜂1 + 𝑑/𝑐. The conformal duration signal measured by the detector is the same as at the source, but the physical time intervals are different at the points of emission and detection.
    (2.60)  𝛿𝑡1 = 𝑎(𝜂1)𝛿𝜂   and   𝛿𝑡0 = 𝑎(𝜂0)𝛿𝜂.
If 𝛿𝑡 is the period of the light wave, then the light is emitted with wavelength 𝜆1 = 𝑐𝛿𝑡1, but is observed with wavelength 𝜆0 = 𝑐𝛿𝑡0, so that
    (2.61)  𝜆0/𝜆1 = 𝑎(𝜂0)/𝑎(𝜂1),
which agree with the result in (2.57).
   It is conventional to define the redshift as the fractional shift in the wavelength:
    (2.62)  𝑧 ≡ (𝜆0 - 𝜆1)/𝜆1.
By comparing the observed wavelengths with those measured in a laboratory on Earth, we determine the redshift. Using (2.61), and setting 𝑎(𝑡0) ≡ 1, we can write the redshift parameter as
    (2.63)  1 + 𝑧 = 1/𝑎(𝑡1)
For example, a galaxy at 𝑧 = 1 emitted the observed light when the universe was half its current size. The CMB photons were released at 𝑧 = 1100 and the first galaxies formed around redshift 𝑧 ∼ 10.
   For nearby sources at 𝑧 < 1, we can expand the scale factor in a power series around 𝑡0:
    (2.64)  𝑎(𝑡1) = 1 + (𝑡1 - 𝑡0)𝐻0 + ∙ ∙ ∙ ,
where 𝑡0 - 𝑡1 is the look-back time and 𝐻0 is the Hubble constant
    (2.65)  𝐻0 ≡ 𝑎̇(𝑡0)/𝑎(𝑡0).
Equation (2.63) then gives 𝑧 = 𝐻0(𝑡0 - 𝑡1) + ∙ ∙ ∙ , For close objects, 𝑡0 - 𝑡1 is simply equal to 𝑑/𝑐, so that the redshift increase linearly with distance. This linear relation is called the Hubble-Lemaitre law. In terms of the recession speed of the object, 𝑣 = 𝑐𝑧, it reads
    (2.66)  𝑣 = 𝑐𝑧 ≈ 𝐻0𝑑.
Hubble's original measurement of the velocity-distance relations of galaxies are shown in Fig. 2.4. For distant objects (𝑧 > 1), we have to be more careful about the meaning of "distance".

          2.2.3 Distances  
   Measuring distances in cosmology is notoriously difficult. The distances appearing in the metric are not observable. Even the physical distance 𝑑phs = 𝑎(𝑡)𝜒 cannot be observed because it is the distance between separated events at a fixed time. A more practical definition of  "distance" must take into account that the universe is expanding and that it takes light a finite amount of time to reach us.

          Luminosity distance  
An important way to measure distances in cosmology uses standard candles. These are objects of known intrinsic brightness, so that observed brightnesses can be used to determine their distances.
   Hubble used Cepheids to discover the expansion of the universe. These are stars whose brightness vary periodically. The observed periods were found to be correlated with the intrinsic brightness of stars. By measuring the time variation of Cepheids, astronomers can infer their absolute brightness and then use their observed brightness to infer their distances. To measure larger distances we need brighter sources. These are provided by type Ia supernovae-stellar explosions that arise when a white dwarf accretes too much matter from a companion star. Supernovae are rare (roughly a few per century in a typical galaxy), but outshine all stars in the host galaxy and can therefore be seen out to enormous distances. By observing many galaxies, astronomers can then measure a large number of supernovae.
   The supernovae explosions occur at relatively precise moment - when the mass of the white dwarf exceeds the Chandrasekar limit - and therefore have fixed brightness. Residual variations of their brightness can be corrected for phenomenologically. The use of supernovae as standard candles have been instrumental in the discovery of the acceleration of the universe and they continue to play an important role in observational cosmology.5
   Let us assume that we have identified n astronomical object with a known luminosity 𝐿 (= energy emitted per unit time). The observed flux 𝐹 (= energy per unit time per receiving area) can then be used to infer its (luminosity) distance. Our task is to determine the relation between 𝐿 and 𝐹 in an expanding universe.
   Consider a source at a redshift 𝑧. The comoving distance to the object is
    (2.67)  𝜒(𝑧) = 𝑡0𝑡1 𝑑𝑡/𝑎(𝑡) = 𝑧0 𝑑𝑧/𝐻(𝑧),
where the redshift evolution of the Hubble parameter, 𝐻(𝑧), depends on the matter content of the universe (see Section 2.3).  We assume That the source emits radiation isotropically (see Fig. 2.5). In a static Euclidean space, the energy would then spread uniformly over a sphere of area 4π𝜒2, and the fraction going through an area 𝐴 (e.g. the collecting area of a telescope) is 𝐴/4π𝜒2. The relation between the absolute luminosity and the observed flux would then be
    (2.68)  𝐹 = 𝐿/4π𝜒2   (static space).
In an expanding spacetime, this result is modified for three reasons:
1. When the light reaches the Earth, at time 𝑡0, a sphere with radius 𝜒 has and area
    (2.69)  4π𝑎2(𝑡0)𝑑2𝑀,
where 𝑑𝑀 ≡ 𝑆𝑘 (𝜒) is the"metric distance" defined in (2.22). In a curved space, the metric distance 𝑑𝑀 differs from the radius 𝜒.
2. The arrive of the photons is smaller than the rate at which they are emitted at the source by a factor of a(𝑡1)/ a(𝑡0) = 1/(1 + 𝑧); cf. Fig. 2.3. This reduces the observed flux by the same factor.
3. The energy 𝐸0 = 𝘩𝑓0 of the observed photons is less than the energy 𝐸1 = 𝘩𝑓1 by the same redshift factor 1/(1 + 𝑧). This lowers the observed flux by another factor of 1/(1 + 𝑧).
Hence, the correct formula is
    (2.70)  𝐹 = 𝐿/4π(𝑡0)𝑑2𝑀(1 + 𝑧)2 ≡ 𝐿/4π𝑑2𝐿 .
In the second equality, we have defined the luminosity distance, 𝑑𝐿, so that the relation between luminosity, flux and luminosity instance is the same as in (2.68).
Hence, we find
    (2.71)  𝑑𝐿(𝑧) = (1 + 𝑧)𝑑𝑀(𝑧) ,
where the metric distance for an object with redshift 𝑧 depends on the cosmological parameters. Figure 2.6 shows the luminosity distance as a function of redshift in a universe with and without dark energy. WE see that the luminosity distance out to a fixed redshift is larger in a dark energy-dominated universe than in a matter-only universe.
   For objects at low redshifts (𝑧 <1), we can define perturbative corrections to Hubble's law (2.66). We first extend the Taylor expression of 𝑎(𝑡) in (2.64) to higher order in the look-back time    (2.72)  𝑎(𝑡) = 1 + 𝐻0(𝑡 - 𝑡0) - 1/2 𝑞0𝐻02(𝑡 - 𝑡0)2 + ∙ ∙ ∙ ,
where we have defined
   (2.73)  𝑞0 ≡ -(𝑑𝑎̇/𝑑𝑡)/𝑎𝐻2𝑡=𝑡0.
The parameter 𝑞0 was named as the deceleration parameter.
Today, we know that it is negative, 𝑞0 ≈ -0.5, and hence measures the acceleration of the universe. Substituting (2.72) into (2.63), we obtain the redshift as a function of the look-back time
   (2.74)  𝑧 = 1/𝑎(𝑡1) - 1 = 𝐻0(𝑡0 - 𝑡1) +1/2 (2 + 𝑞0)𝐻02(𝑡0 - 𝑡1)2 + ∙ ∙ ∙ .
This can be inverted to give
   (2.75)  𝐻0(𝑡0 = 𝑧 - 1/2(2 + 𝑞0)𝑧2 + ∙ ∙ ∙ ,
where the higher-order terms can be ignored as long as 𝑧 < 1. Using (2.72), we can also write the comoving distance in terms of the look-back time and the redshift    (2.76)  𝜒 = 𝑐 𝑡0𝑡1 𝑑𝑡/𝑎(𝑡) = 𝑡0𝑡1 𝑑𝑡[1 + 𝐻0(𝑡 - 𝑡0) + ∙ ∙ ∙ ] = 𝑐(𝑡 - 𝑡0) + 1/2 𝐻0/𝑐 𝑐2(𝑡 - 𝑡0)2 + ∙ ∙ ∙ = 𝑐/𝐻0 [𝑧 -1/2(1 + 𝑞0)𝑧2 + ∙ ∙ ∙ ].
Through (2.71) and (2.22), the determines the luminosity distance as a function of the redshift, 𝑑𝐿(𝑧) . For a flat universe, with 𝑆𝑘(𝜒) = 𝜒, the modified Hubble-Lemaître law reads
   (2.77)  𝑑𝐿 = 𝑐/𝐻0[𝑧 + 1/2(1 - 𝑞0)𝑧2 + ∙ ∙ ∙ ].
The value of 𝐻0 and 𝑞0 can be extracted by fitting the functional form to the observed 𝑑𝐿(𝑧). The value of 𝑞0 will depend on the energy content of the universe. The results of such a measurement in section 2.4 will be presented.
   Measurements of the Hubble constant used to com with very large uncertainties. It therefore become conventional to define  
   (2.78)  𝐻0 ≡ 100𝘩 km s-1Mpc-1,
where the parameter 𝘩 is used to keep track of how uncertainties in 𝐻0 propagate to the inferred value of other cosmological parameters. The latest supernovae measurements have found
   (2.79)  𝘩 = 0.730 ± 0.010    (supernovae),
The Hubble constant cal also be extract from the CMB anisotropy spectrum (see Chapter 7). These observations gives
   (2.80)  𝘩 = 0.674 ± 0.005    (CMB).
As we can see, there is currently a statistically significant discrepancy between the two measurements. It is unclear whether this "Hubble tension" is due to an unidentified observational systematic a breakdown in the standard cosmological model.  

          Angular diameter distance   
  An alternative way to measure distances is to use standard rulers, i.e. objects of known physical size. The observed angular sizes of such objects then depends on their distances. As we will see in Chapter 7, the typical size of hot and cold spots in the CMB can be predicted theoretically and is therefore a standard ruler. The observed angular size of these spots then determines the distance to the CMB's surface of last-scattering.6
   Let us assume that an object is at a comoving distance 𝜒 and that the photons emitted at a time 𝑡1 (see Fig.2.7). The transverse physical size of the object is 𝐷. In static Euclidean space, we would expect its angular size to be
   (2.81)  𝛿𝜃 = 𝐷/𝜒   (static space),
where we assumed that 𝛿𝜃 ≪ 1 (in radian), which is true for all cosmological objects. In an expanding universe, this formula becomes
   (2.82)  𝛿𝜃 = 𝐷/𝑎(𝑡1)𝑑𝛭 ≡ 𝑑𝛢   (expanding space),
where metric distance 𝑑𝛭 ≡ 𝑆𝑘(𝜒). Notice that the observed angular size depends on the distance at time 𝑡1 when the light was emitted. The second equality in (2.820  has defined the angular diameter distance by analogy with Euclidean formula (2.81). In terms of the metric distance 𝑑𝛭 and redshift 𝑧. the angular diameter distance is
   (2.83)  𝑑𝛢(𝑧) = 𝑑𝛭(𝑧)/(1 + 𝑧).
Fig. 2.8 shows the angular diameter as a function of redshift in a flat matter-only universe and in a universe with negative spatial curvature. We see that the angular diameter distance starts to decrease around 𝑧𝑚 ~ 1.5. At redshift larger than 𝑧𝑚 objects of a given proper size will appear bigger on the sky with increasing redshift. The effect is due to the expansion of the universe. The spacetime was compressed when the light was emitted and the objected were closer to us. The observered anguar size is therefore larger.

5 In the future gravitational waves (GWs) will allow for robust measurement distance using so-called standard sirens. The parameters of source like the masses of the objects in a binary system is determined by GWs signals and GR predicts the emitted GW power. Comparing these data provides a clean measurement of luminosity distance.

          2.3 Dynamics
So far, we have used the symmetries of the universe to fix its geometry and studied the propagation of particles in the expending spacetime. The scale factor 𝑎(𝑡) has remained an unspecified function of time. The evolution of the scale factor follows from the Einstein equation
    (2.84)   𝐺𝜇𝜈 ( + 𝛬𝑔𝜇𝜈) = 8π𝐺/𝑐4 𝑇𝜇𝜈,   [𝛬: cosmological constant, 𝑔𝜇𝜈:metric tensor]
where 𝐺 = 6.67 × 10-11 m3 kg-1 s-2 is Newton's constant. This relates the Einstein tensor 𝐺𝜇𝜈 (a measure of the "spacetime curvature" of the universe) to the energy-momentum tensor 𝑇𝜇𝜈 (a measure of "matter content" of the universe). We will first discuss the possible forms of cosmological energy-momentum tensors, then compute the Einstein tensor for FRW background, and finally put them together to solve for the evolution of the scale factor 𝑎(𝑡) as a function of the matter content.

          2.3.1 Perfect Fluids   
We have seen how the spacetime geometry of the universe is constrained by homogeneity and isotropy. Now, we will determine which types of matter are consistent with these symmetries. We will find that the coarse-grained energy-momentum tensor is required to be that of a perfect fluid.
    (2.85)  𝑇𝜇𝜈 = (𝜌 + 𝑃/𝑐2)𝑈𝜇𝑈𝜈 + 𝑃𝑔𝜇𝜈,
where 𝜌𝑐2 and 𝑃 are the energy density and pressure in the rest frame of the fluid, and 𝑈𝜇 is its 4-velocity relative to a comoving observer. ]

          Number density 
Let us a simpler object: the number current 4-vector 𝑁𝜇. 𝑁0 measures the number density particles, where a "particle" in cosmology may be   an entire galaxy. 𝑁𝑖 is the flux of particle in the direction 𝑥𝑖. We call  𝑁0 a three scalar because its value doen't change under a purely spatial coordinate transformation. But 𝑁𝑖 transforms like a 3-vector under such a transformation. We want to determine which form of the number current is consistent with the homogeneity and isotropy seen by a comoving observer.
   Isotropy requires that the mean value of any 3-vector, such as 𝑁𝑖, must vanish, and homogeneity require that the mean value of 3-scalar such as 𝑁0, is only a function of time. Hence
    (2.86)  𝑁0 = 𝑐𝑛(𝑡),     𝑁𝑖 = 0,
where 𝑛(𝑡) is the number of galaxies per proper volume. A general observer (i.e. an observer in motion relative to the men rest frame of the particles), would measure the following number current 4-vector
    (2.87)  𝑁𝜇 = 𝑛𝑈𝜇,
where 𝑈𝜇 ≡ 𝑑𝑥𝜇/𝑑𝜏 is relative 4-velocity between particles and the observer. We recover (2.86) for a comoving observer, with 𝑈𝜇 = (𝑐, 0, 0, 0). Moreover, for 𝑈𝜇 = 𝛾(𝑐, 𝑣𝑖, the expression (2.87) gives the correctly boosted result, where 𝛾 is the Lorentz factor for the fact that one of the dimensions is Lorentz contracted.
   How does the number density evolve with time? If the number of particles is conserved, then the rate of of change of number density must equal the divergence of the flux of particles. In Minkowski space, this imply the following continuity equation0𝑁0 = -∂𝑖𝑁𝑖, or in relativistic notation,
    (2.88)  ∂𝜇𝑁𝜇 = 0.
Equation (2.89) is generalized to curved spacetimes by replacing the partial derivative with a covariant derivative (see Appendix A)
    (2.89)  ∇𝜇𝑁𝜇 = 0.
This covariant form of the continuity equation is valid independent of the choice of coordinates.

Covariant derivative     The covariant derivative is an important object in differential geometry and it is fundamental importance in general relativity. But we will not get into these detail here and simply tell us that how the covariant derivatives acts on 4-vectors with upstairs and downstairs indices:
    (2.90-91)   ∇𝜇𝐴𝜈 = ∂𝜇𝐴𝜈 + 𝑁𝜇,     ∇𝜇𝛣𝜈 = ∂𝜇𝛣𝜈 - 𝛤𝜆𝜇𝜈𝛣𝜆.
We already encounter (2.91) in our discussion of the geodesic equation in (2.43),  [Wikipedia Covariant derivative] The action on a general tensor is straightforward generalization of these two results. For example, the covariant derivative of a rank-2 tensor with mixed indices is
    (2.92)    ∇𝜇𝛵𝜎𝜈 = ∂𝜇𝛵𝜎𝜈 + 𝛤𝜎𝜇𝜆𝛵𝜆𝜈 - 𝛤𝜆𝜇𝜈𝛵𝜎𝜈.

   Using (2.91) in (2.90, we get
    (2.93)    ∂𝜇𝑁𝜇 = -𝛤𝜇𝜇𝜆𝑁𝜆.
Let us evaluate this in the rest frame of fluid. Substituting the components of the number current in (2.86), we obtain
    (2.94)    𝑑𝑛/𝑐 𝑑𝑡 = -𝛤𝜇𝜇0 𝑛 = -3/𝑐 𝑎̇/𝑎 𝑛,   [𝑐 𝑑𝑛/𝑐 𝑑𝑡 = -𝛤𝜇𝜇0 𝑐 𝑛]
where we have used that 𝛤000 = 0 and 𝛤𝑖𝑖0 = -3/𝑐 𝑎̇/𝑎. Hence, we find that
    (2.95)    𝑛̇/𝑛 = -3𝑎̇/𝑎  ⇒   𝑛(𝑡) ∝ 𝑎-3  [ 𝑛̇/𝑛 𝑑𝑡 = 1/𝑛 𝑑𝑛 = log(𝑛) + const; -3𝑎̇/𝑎 𝑑𝑡 = -3/𝑎 𝑑𝑎 = log(1/𝑎3) + const]
As expected, the number density decreases in proportion to the increase of the proper volumne, 𝑉 ∝𝑎3.
          Energy-momentum tensor 
We will now use a similar logic to determine which form of the energy-momentum tensor 𝛵𝜇𝜈 is consistent with the requirement of homogeneity and isotropy. First, we decompose 𝛵𝜇𝜈 into a 3-scalar 𝛵00, two 3-vectors  𝛵𝑖0 and 𝛵0𝑗 and a 3-tensor 𝛵𝑖𝑗. The physical meaning of these component is
    (2.96)    𝛵𝜇𝜈 = (𝛵00, 𝛵0𝑗, 𝛵𝑖0, 𝛵𝑖𝑗) = (energy density, momentum density, energy flex, stress tensor).
In a homogeneous universe, the energy density must be independent of position, but can depend on time, 𝛵00 = 𝜌(𝑡)𝑐2. Moreover, isotropy again requires the mean values of the 3-vectors in the comoving frame, 𝛵𝑖0 = 𝛵0𝑗 = 0. Finally isotropy around a point 𝐱 = 0 constrains the mean value of 3-tensor, such as  𝛵𝑖𝑗, to be proportional to 𝛿𝑖𝑗. Since the metric 𝑔𝑖𝑗 equals 𝑎2𝛿𝑖𝑗 at 𝐱 = 0, we have
    (2.97)   𝛵𝑖𝑗(𝐱 = 0)  ∝ 𝛿𝑖𝑗 ∝ 𝑔𝑖𝑗(𝐱 = 0).
Homogeneity requires the proportionality coefficient to be only a function of time. Moreover, Since this is a proportionality between two tensors, 𝛵𝑖𝑗 and 𝑔𝑖𝑗, it remains unaffected by transformation of the spatial coordinates, including those transformations that preserve the form of 𝑔𝑖𝑗 while taking this origin into any other point. Hence homogeneity and isotropy require the component s of energy-momentum tensor everywhere to take the form
    (2.98)   𝛵00 ≡ 𝜌(𝑡)𝑐2,   𝛵𝑖0 ≡ 𝑐𝜋𝑖 = 0,   𝛵𝑖𝑗 = 𝑃(𝑡)𝑔𝑖𝑗(𝑡, 𝐱).
Raising one of indices, we find [for example?]
    (2.99)  𝛵𝜇𝜈 = 𝑔𝜇𝜈𝛵𝜇𝜈 = diag(-𝜌𝑐, 𝑃, 𝑃, 𝑃).
which we recognize as the energy-momentum tensor of a perfect fluid in the frame of a comoving observer. More generally, the energy-momentum tensor can be written in the following, explicitly covariant, form [RE (2.84)]
    (2.100)  𝑇𝜇𝜈 = (𝜌 + 𝑃/𝑐2)𝑈𝜇𝑈𝜈 + 𝑃𝑔𝜇𝜈 where 𝑈𝜇 is the relative 4-velocity between the fluid and the observer. We can recover (2.98) for a comoving observer, 𝑈𝜇 = (𝑐, 0, 0, 0). [Why not 𝑈𝜇?]

          Continuity equation    
In Minkowski space energy and momentum are conserved. The energy density therefore satisfied the continuity equation ῤ = -∂𝑖π𝑖, i.e. the rate of change of the density equals the divergence of the energy flux π. Similarly the evolution of momentum satisfies the Euler equation 𝑑π𝑖/𝑑𝑡 = ∂𝑖𝛲. These conservation laws can be combined  into a 4-component conservation equation for the energy-momentum tensor
    (2.101)  ∂𝜇𝑇𝜇𝜈 = 0.
In GR this id promoted to the covariant conservation equation
    (2.102)  𝜇𝑇𝜇𝜈 = 0.
Using (2.92)
    (2.103)  ∇𝜇𝑇𝜇𝜈 = ∂𝜇𝛵𝜇𝜈 + 𝛤𝜇𝜇𝜆𝛵𝜆𝜈 - 𝛤𝜆𝜇𝜈𝛵𝜇𝜆 = 0.
This corresponds to four separate equation (𝜈: 0~3).  The evolution of the energy density is determined by the 𝜈 = 0 equation
    (2.104)  ∂𝜇𝛵𝜇0 + 𝛤𝜇𝜇𝜆𝛵𝜆0 - 𝛤𝜆𝜇0𝛵𝜇𝜆 = 0.
Since 𝛵𝑖0 vanishes by isopropy, this reduces to [∂𝜇𝛵00 + 𝛤𝜇𝜇𝜆𝛵00 - 𝛤𝜆𝜇0𝛵𝜇𝜆 = 0.]
    (2.105)  1/𝑐 𝑑(𝜌𝑐2)/𝑑𝑡 + 𝛤𝜇𝜇0(𝜌𝑐2) - 𝛤𝜆𝜇0𝛵𝜇𝜆 = 0,
where 𝛤𝜆𝜇0 vanishes unless 𝜆 and 𝜇 are spatial indices 𝑖 and they are same, i.e. 𝜆 = 𝜇 = 𝑖. So we have 𝛤𝑖𝑖0 = 3𝑐-1 𝑎̇/𝑎. [RE (2.45) and 𝛵𝜇𝜆 = 𝛵𝑖𝑖 = 𝑃.] The continuity equation (2.105) then becomes
    (2.106)  𝜌̇ + 3 𝑎̇/𝑎 (𝜌 + 𝑃/𝑐2) = 0.   [𝑐 𝑑𝜌/𝑑𝑡 + 3𝑐 𝑎̇/𝑎 (𝜌 + 𝑃/𝑐2) = 0.]
This important equation describes "energy conservation" in the cosmological context. Notice that the usual notion of energy conservation in flat space relies on a symmetry under the translations. This symmetry is broken in an expanding space, so the familiar energy conservation does not have to hold and is replaced by (2.106).

Exercise 2.4   Show that (2.106) can be obtain from the thermodynamic relation 𝑑𝑈 = -𝑃𝑑𝑉, where 𝑈 = (𝜌𝑐2)𝑉 and 𝑉 ∝𝑎3. [Solution]   Using 𝑈 = (𝜌𝑐2)𝑉, we have 𝑑𝑈 = 𝑐2𝑉(𝑑𝜌 + 𝜌 𝑑𝑉/𝑉) and with 𝑑𝑈 = -𝑃𝑑𝑉 becomes the following and then we used  𝑉 ∝𝑎3 in the final equality.
   (a)   𝑑𝜌 = - 𝑑𝑉/𝑉(𝜌 + 𝑃/𝑐2) = -3 𝑑𝑎/𝑎 (𝜌 + 𝑃/𝑐2),
   (b)   (𝜌 + 𝑃/𝑐2) log  𝑉 + const =  (𝜌 + 𝑃/𝑐2) log 𝑎3 + const)
By taking a derivative to time 𝑡 we get the continuity equation,
   (c)   𝑑𝜌/𝑑𝑡 =  -3 𝑎̇/𝑎 (𝜌 + 𝑃/𝑐2).    ⇒    𝜌̇ + 3 𝑎̇/𝑎 (𝜌 + 𝑃/𝑐2) = 0.  ▮

   Most cosmological fluids can be parameterized in terms of a constant equation of state, 𝜔 = 𝛲/(𝜌𝑐2). In that case, we get     (2.107)  𝜌̇/𝜌 = -3(1 + 𝜔) 𝑎̇/𝑎    ⇒    𝜌 ∝ 𝑎-3(1 + 𝜔)     [ 𝜌̇/𝜌 𝑑𝑡 = log(𝜌) + const; [-3(1 + 𝜔) 𝑎̇/𝑎] 𝑑𝑡 = log[𝑎-3(1 + 𝜔)] + const]
which shows how the dilution of the energy density depends on the equation of state.

          2.3.2 Matter and Radiation    
The term matter will be used to refer to a fluid whose pressure is much smaller than its energy density, ∣𝛲∣≪ 𝜌𝑐2. As we will see in Chapter 3, this is the case for a gas of non-relativistic particles, for which the energy density is dominated by their rest mass. Setting 𝜔 = 0 in (2.107) gives
    (2.108)  𝜌 ∝ 𝑎-3.
This dilution of the energy density simply reflects that the fact the volume of a region of space increases as 𝑉 ∝ 𝑎3, while the energy within the region stays constant.

Baryons   Cosmologists refers to ordinary matter (nuclei and electrons) as baryons.Electrons are leptons, but nuclei are so much heavier than electrons that most of the mass is in this baryons.

Dark Matter   Most of the matter in the universe is in the form of dark matter. Figure 2.9 shows the orbital speeds of visible stars or gas in the galaxy M33 versus their radial distance from the center of the galaxy. We see that the rotation speeds stay constant for behind the extent of the visible disc. This suggests that there is an invisible halo of dark matter that holds the galaxy together. On larger scale, dark matter has been detected  by gravitational lensing. As the CMB photons travel through the universe they get deflected by the total matter in the universe. The effect can be measured statistically and provides one of the best pieces of evidence for dark matter on a cosmic scale.

   The precise nature of the dark matter is unknown. We usually think of it as a new particle species, but we don't know what it really is. There are many popular dark matter candidates such as WIMPs, axions, MACHOs, and primordial black holes. [Wikipedia Dark matter:] Wile finding a microscopic detail don't affect the large-scale evolution of the universe. On large scales, all dark matter models are described by the same pressureless fluid. This cold dark matter (CDM) is an integral part of the standard model of cosmology.
   The term radiation will be used to denote for which the pressure is on third of the energy density, 𝛲 = 1/3 𝜌𝑐2. This is the case for a gas of relativistic particles, for which the energy density to dominated by the kinetic energy. Setting 𝜔 = 1/3 in (2.107) gives
    (2.109)  𝜌 ∝ 𝑎-4.
The dilution now includes not just the expansion, 𝑉 ∝ 𝑎3, but also the redshifting of the energy of the particles, 𝐸 ∝ 𝑎-1.

Light particles   At early times, all particles of the Standard Model acted as relativistic, because the temperature of the universe was larger than the masses of the particles. As the temperature of the universe dropped, the massless of many particles became relevant and they started behave like matter.

Photons   Being massless, photons are always relativistic. Together with neutrinos, they ere the dominant energy density during Big Bang nucleosynthesis. Today, we observe these photons in the form of the CMB.

Neutrinos  For most of history of the universe neutrinos behaves like radiation. Only recently have their small masses become relevant, making them act like matter.

Gravitons  The early universe may also have produced a background of gravitons. The density of these gravitons is predicted to be very small, so they have a negligible effect on the expansion of the universe. Nevertheless, experimental efforts are underway to detect them (see Section 8.4.2).

          2.3.3 Dark Energy 
    We have recently learned that matter and radiation aren't enough to describe the evolution of the universe. Instead the universe today to determined by a mysterious form of dark energy with negative pressure,𝛲 = -𝜌𝑐2 and hence constant energy density.
    (2.110)  𝜌 ∝ 𝑎0
Since the energy density doesn't dilute, energy has to created on the universe expands. As described above, that doesn't violate the conservation of energy, as long as equation (2.106) is satisfied.

Vacuum energy   A natural candidate for a constant energy density is the energy associated to empty space itself.As the universe expands, more space is being created and this energy therefore increase in proportion to the volume. In quantum field theory, this so-called "vacuum energy" in actually predicted, leading to an energy-momentum tensor of the form
    (2.111)  𝛵vac𝜇𝜈 = -𝜌vac𝑐2𝑔𝜇𝜈.
AS expected from Lorentz symmetry, the energy-momentum tensor associated to the vacuum to proportional to the spacetime metric. Comparison with (2.100) shows that this indeed gives 𝛲vac = -𝜌vac𝑐2. Unfortunately, as it will be described below, quantum field theory also predicts the size of the vacuum energy 𝜌vac to be much larger than the value inferred from cosmological observations.

Cosmological constant   The observation of dark energy has also revived the old concept of a "cosmological constant," originally introduced by Einstein to make the universe static. Note that the left-hand side of Einstein equation (2.94) isn't uniquely defined. We can add the term 𝛬𝑔𝜇𝜈 for some constant 𝛬, without changing the conservation of the energy-momentum tensor, ∇𝜇𝛵𝜇𝜈 = 0. To see this, you need to convince yourself that ∇𝜇𝑔𝜇𝜈 = 0. In other words, we could have written the Einstein equation as
    (2.112)  𝐺𝜇𝜈 + 𝛬𝑔𝜇𝜈 = 8π𝐺/𝑐4 𝑇𝜇𝜈.
However it has been standard practice to move this extra terms to the right-hand side and treat it as a contribution to the energy-momentum tensor
    (2.113)  𝛵(𝛬)𝜇𝜈 = 𝛬𝑐4/8π𝐺 𝑔𝜇𝜈 ≡ -𝜌𝛬𝑐2𝑔𝜇𝜈,
which is of the same form as (2.111).

Dark energy   The therm "dark energy" is often used to describe a more general fluid whose equation of state is not exactly that of a cosmological constant 𝜔 ≈ -1, or may even be varying in time. It is the failure of quantum field theory to explain the size of the observed vacuum energy that has led theorists to consider those more exotic possibilities. Whatever it is, dark energy plays a key role in the standard cosmological model-the 𝛬CDM model (see Section 2.4).

          The cosmological constant problem    
When the cosmological constant was discovered, it came as a relief to observers, but was a shock to theorists. While it reconciled the age of the universe with the age of the oldest starts , its observed value is much smaller than all particle physics scales, making it hard to understand from a more fundamental perspective. This cosmological constant problem is the biggest crisis in modern theoretical physics.
   In Section 2.4. we will see that the observed value of the vacuum energy is
    (2.114)  𝜌𝛬𝑐2 ≈ 6 × 10-10 J m-3
To compare this to our expectation from particle physics, we had better to write it in units of high-energy physics, electron volts (eV). Using 1 J = 6.2 × 1018 eV and ħ𝑐 ≈ 2.0 × 10-7 eV m, we get (ħ𝑐)3𝜌𝛬𝑐2 = (10-3 eV)4. Written in natural units, with  ħ = 𝑐 ≡ 1, we have then
    (2.115)  𝜌𝛬 = (10-3 eV)4.
We see that the scale appearing in the vacuum energy, 𝑀𝛬 ∼ 10-3 eV, is much smaller than the typical scales relevant to particle physics.    Quantum field theory (QFT) predicts the existence of vacuum energy. However, the expected value of this vacuum energy is vastly too large. To start, recall that that in QFT every particle arises as an expectation of a fundamental field. Moreover, each field can be represented by an infinite number of Fourier modes with frequencies 𝜔𝜅. These Fourier modes satisfy the equation of a harmonic oscillator and therefore experience the same zero-point fluctuations as a quantum harmonic oscillator (see Section 8.2.1). In other words, the vacuum energy receive contributions of the form 1/2 ℏ𝜔𝜅 for each mode. The sum over all Fourier modes actually diverges. This divergence arises because we extrapolated our QFT beyond  its regime of validity. Let us therefore assumed that our theory is valid only up to a cutoff scale 𝛭* and only contributions to the vacuum energy from modes with frequencies below the cutoff. The vacuum energy will now be finite, but depends on the arbitrary cutoff scale. The dependence on the cutoff can be removed by adding a counterterm in the form of a bare cosmological constant 𝛬0. After this process of renormalization, the remaining vacuum energy is
    (2.116)  𝜌QFT ∼ 𝛴𝑖 𝑚4𝑖,
where the sum is over all particles with mass below the cutoff. In the absence of gravity this constant vacuum energy wouldn't affect any dynamics and is therefore  usually discarded. The equivalence principle, however,implies that all forms of energy gravitate and hence affect the curvature of the spacetime. The vacuum energy is no exception.
   The first to worry about the gravitational effects of zero-point energies was Wolfgang Pauli in the 1920s. Considering the contribution from the electron in (2.1116), he estimated that the induced curvature radius of the universe would be 106 km, so that "the world would not even reach to the moon". Including rest of the Standard Model only makes the problem worse:
    (2.117)  𝜌QFT ≳ (1 TeV)4 = 1060 𝜌𝛬,
where we have added contributions up to the TeV scale. The enormous discrepancy between this estimate and the observed value in (2.114) is the cosmological constant problem.
   But we can add an arbitrary constant to the QFT estimate to match the observed value of this vacuum energy
    (2.118)  𝜌𝛬 = 𝜌QFT + 𝜌0.
To explain the small size of the observed vacuum energy would require two large numbers,𝜌QFT and  𝜌0 have 60 digits in common, but differ at the 61st digit,  so that the sum of the two is smaller by 60 orders of magnitude. moreover, each time the universe goes through a phase transition, the value of 𝜌QFT changes, while the value of 𝜌0 presumably doesn't. For example, we expect the electroweakland QCD phase transition to induce jumps in the order of ∆𝜌QFT ∼ (200 GeV)4 and (0.3 GeV)4 respectively.Any tuning must explain the small value of the cosmological constant today and not at the beginning.
   One way to explain the apparent fine-tuning to the vacuum energy is to appeal to the anthropic principle. Suppose that our universe is part of a much larger multiverse and that the fundamental physical parameters exhibit different values indifferent regions of space. In particular, imagine that the value of the vacuum energy varies across the multiverse. If the vacuum energy were much larger, dark energy would start to dominate before galaxies would have formed and complex structures could not have evolved. In other words, we shouldn't be shocked by the small value of the vacuum energy, since if it was any bigger  w would not be around to ask the question. "We live where we can live" in a vast landscape of possibilities and the observed value of the cosmological constant is simply the accident of "environmental selection."

          2.3.4 Spacetime Curvature  
   Having introduced the relevant types of matter and energy in the universe, we now want to see how they source the dynamic s of the spacetime. To do this, we have to compute the Einstein tensor on the left-hand side of the Einstein equation (2.84)
    (2.119)  𝐺𝜇𝜈 = 𝑅𝜇𝜈 - 1/2 𝑅𝑔𝜇𝜈,
where 𝑅𝜇𝜈 is the Ricci tensor and 𝑅 = 𝑅𝜇𝜇 = 𝑔𝜇𝜈𝑅𝜇𝜈 is its trace, the Ricci scalar. In Appendix A, we give the following definition of the Ricci tensor
    (2.120)  𝑅𝜇𝜈 ≡ ∂𝜆𝛤𝜆𝜇𝜈 - ∂𝜈𝛤𝜆𝜇𝜆 + 𝛤𝜆𝜆𝜌𝛤𝜌𝜇𝜈 - 𝛤𝜌𝜇𝜆𝛤𝜆𝜈𝜌.
Now we are going to compute (2.120) and (2.119) for the FRW spacetime. 𝑅𝑖0 = 𝑅0𝑖 = 0, because it is a 3-vector and therefore must vanish due to the isotropy of Robertson-Walker metric. The non- vanishing components of Ricci tensor are
    (2.121)  𝑅00 = -3/𝑐2 (𝑑𝑎̇/𝑑𝑡)/𝑎,
    (2.122)  𝑅𝑖𝑗 = 1/𝑐2 [(𝑑𝑎̇/𝑑𝑡)/𝑎 + 2 (𝑎̇/𝑎)2 + 2 𝑘𝑐2/𝑎2𝑅02] 𝑔𝑖𝑗.

Example   Setting 𝜇 = 𝜈 = 0 in (2.120), we have
    (2.123)  𝑅00 ≡ ∂𝜆𝛤𝜆00 - ∂0𝛤𝜆0𝜆 + 𝛤𝜆𝜆𝜌𝛤𝜌00 - 𝛤𝜌0𝜆𝛤𝜆0𝜌.
Since Christoffel symbols with two time indices-00- vanish, this reduces to
    (2.124)  𝑅00 ≡ -∂0𝛤𝑖0𝑖 - 𝛤𝑖0𝑗𝛤𝑗0𝑖.
Using 𝛤𝑖0𝑗 = 𝑐-1(𝑎̇/𝑎)𝛿𝑖𝑗, {RE (2.45)] we find
    (2.125)  𝑅00 = -1/𝑐2 𝑑/𝑑𝑡 (3 𝑎̇/𝑎) - 3/𝑐2 (𝑎̇/𝑎)2 = -3/𝑐2 (𝑑𝑎̇/𝑑𝑡)/𝑎. ▮
Example   Computing 𝑅𝑖𝑗 can be greatly simplified using the following trick: we will compute 𝑅𝑖𝑗 at 𝐱 = 0 where the spatial metric is 𝛾𝑖𝑗 = 𝛿𝑖𝑗 and then argue that the result for general 𝐱 must have the form 𝑅𝑖𝑗 ∝ 𝑔𝑖𝑗. [RE (2.49) In FRW metric 𝑔𝑖𝑗 = 𝑎2𝛾𝑖𝑗]
In Cartesian coordinates the spatial metric is [RE (2.9-14)]
    (2.126)  𝛾𝑖𝑗 = 𝛿𝑖𝑗 + 𝑘𝑥𝑖𝑥𝑗/[𝑅02 - 𝑘(𝑥𝑙𝑥𝑙)]. [Why? (𝐱 ⋅ 𝑑𝐱)2 = 𝑥𝑖𝑥𝑗;   𝐱2 = 𝑥𝑙𝑥𝑙]
The key point is to think ahead and anticipate that we will set 𝐱 = 0 at the end. In this condition the Christoffel symbols contain derivative metric and the Ricci tensor has another derivative, so there will be terms in the final answer with two derivatives acting on the metric from the second term.  We only need to keep terms to quadratic order in 𝑥:  
    (2.127)  𝛾𝑖𝑗 = 𝛿𝑖𝑗 + 𝑘𝑥𝑖𝑥𝑗/𝑅02 + 𝑂(𝑥4).
Plugging this into the definition of Christoffel symbol gives [RE (2.45) for Christoffel symbol in FRW metric]
    (2.128)  𝛤𝑖𝑗𝑘 = 𝑘/𝑅02 𝑥𝑖𝛿𝑗𝑘 + 𝑂(𝑥3).
This vanishes at 𝐱 = 0, but the derivative does not. From the definition of Ricci tensor, we then have
    (2.129)  𝑅𝑖𝑗(𝐱 = 0) ≡ (𝐴){𝜆𝛤𝜆𝑖𝑗 - ∂𝑗𝛤𝜆𝑖𝜆} + (𝐵){𝛤𝜆𝜆𝜌𝛤𝜌𝑖𝑗 - 𝛤𝜌𝑖𝜆𝛤𝜆𝑗𝜌}.
Let us start with (𝐵). Dropping terms that are zero at 𝐱 = 0, we find
    (2.130)  (𝐵) = 𝛤𝑙𝑙0𝛤0𝑖𝑗 - 𝛤0𝑖𝑙𝛤𝑙𝑗0 - 𝛤𝑙𝑖0𝛤0𝑗𝑙 = 3/𝑐2 𝑎̇/𝑎 𝑎𝑎̇𝛿𝑖𝑗 - 1/𝑐2 𝑎𝛿𝑖𝑙 𝑎̇/𝑎 𝑎𝛿𝑖𝑗 - 1/ 𝑐2 𝑎̇/𝑎 𝛿𝑙𝑖𝑎𝑎̇𝛿𝑗𝑙 = 𝑎̇2/𝑐2 𝛿𝑖𝑗.
The two terms labeled (𝐴) can be evaluated by using (2.128),
    (2.131)  (𝐴) = ∂0𝛤0𝑖𝑗 + ∂𝑡𝛤𝑙𝑖𝑗 - ∂𝑗𝛤𝑙𝑖𝑙 = 𝑐-2𝑡(𝑎𝑎̇)𝛿𝑖𝑗 + 𝑘/𝑅02 𝛿𝑙𝑖𝛿𝑖𝑗 - 𝑘/𝑅02 𝛿𝑙𝑗𝛿𝑖𝑙 = 𝑐-2 (𝑎𝑑𝑎̇/𝑑𝑡 + 𝑎̇2 + 2 𝑘𝑐2/𝑅02)𝛿𝑖𝑗.
Hence we get
    (2.132)  𝑅𝑖𝑗(𝐱 = 0) = (𝐴) + (𝐵) = 1/𝑐2[𝑎𝑎̇ + 2𝑎̇2 + 2 𝑘𝑐2/𝑅02]𝛿𝑖𝑗 = 1/𝑐2[𝑎𝑑𝑎̇/𝑑𝑡 + 2𝑎̇2 + 2 𝑘𝑐2/𝑅02]𝛿𝑖𝑗 = 1/𝑐2[(𝑑𝑎̇/𝑑𝑡)/𝑎 + 2(𝑎̇/𝑎)2 + 2 𝑘𝑐2/𝑅02]𝑔𝑖𝑗(𝐱 = 0).
Since this is a relation between tensors, it holds for general 𝐱, so we get the result quoted in (2.122). ▮

Now we can calculate the Ricci scalar [𝑔𝜇𝜈 = diag(-1, 1/𝑎2 𝛾𝑖𝑗)
    (2.133)  𝑅 = 𝑔𝜇𝜈𝑅𝜇𝜈 = -𝑅00 - 𝑔𝑖𝑗𝑅𝑖𝑗 = 3/𝑐2 (𝑑𝑎̇/𝑑𝑡)/𝑎 + 𝑔𝑖𝑗𝑔𝑖𝑗 1/𝑐2[(𝑑𝑎̇/𝑑𝑡)/𝑎 + 2(𝑎̇/𝑎)2 + 2 𝑘𝑐2/𝑅02] = 𝛿𝑖𝑖[(𝑑𝑎̇/𝑑𝑡)/𝑎 + 2(𝑎̇/𝑎)2 + 2 𝑘𝑐2/𝑅02] = 6/𝑐2 [(𝑑𝑎̇/𝑑𝑡)/𝑎 + (𝑎̇/𝑎)2 + 𝑘𝑐2/𝑅02],
and the nonzero components of the Einstein tensor, 𝐺𝜇𝜈 ≡ 𝑔𝜇𝜆𝐺𝜆𝜈, are
    (2.134)  𝐺00 = -3/𝑐2 [(ȧ/𝑎)2 + 𝑘𝑐2/𝑎2𝑅02],
Derivation   From (2.119) 𝐺00 = 𝑔00𝐺00 = -𝐺00.   -𝐺00= -𝑅00 + 1/2 𝑅𝑔00 = 3/𝑐2 (𝑑𝑎̇/𝑑𝑡)/𝑎 + 1/2 6/𝑐2 [(𝑑𝑎̇/𝑑𝑡)/𝑎 + (𝑎̇/𝑎)2 + 𝑘𝑐2/𝑅02](-1) = -3/𝑐2 [(𝑎̇/𝑎)2 + 𝑘𝑐2/𝑎2𝑅02]. ▮
    (2.135)   𝐺𝑖𝑗 = -1/𝑐2 [2(𝑑𝑎̇/𝑑𝑡)/𝑎 + (𝑎̇/𝑎)2 + 𝑘𝑐2/𝑎2𝑅02]𝛿𝑖𝑗
Derivation   𝑔𝑖𝜆𝐺𝜆𝑗 = 𝐺𝑖𝑗.  From (2.122) and (2.133)  𝐺𝑖𝑗 = 𝑅𝑖𝑗 -1/2 𝑅𝑔𝑖𝑗 = 1/𝑐2 [(𝑑𝑎̇/𝑑𝑡)/𝑎 + 2 (𝑎̇/𝑎)2 + 2 𝑘𝑐2/𝑎2𝑅02] 𝑔𝑖𝑗 - 1/2 6/𝑐2 [(𝑑𝑎̇/𝑑𝑡)/𝑎 + (𝑎̇/𝑎)2 + 𝑘𝑐2/𝑅02]𝑔𝑖𝑗 = -1/𝑐2 [2(𝑑𝑎̇/𝑑𝑡)/𝑎 + (𝑎̇/𝑎)2 + 𝑘𝑐2/𝑎2𝑅02] 𝑔𝑖𝑗,  ⇒   𝐺𝑖𝑗 = -1/𝑐2 [2(𝑑𝑎̇/𝑑𝑡)/𝑎 + (𝑎̇/𝑎)2 + 𝑘𝑐2/𝑎2𝑅02]𝛿𝑖𝑗. ▮

          2.3.5 Friedmann Equations  
   Setting 𝐺00 equal to (8π𝐺/𝑐4)𝛵00 = 8π𝐺/𝑐2 (-𝜌𝑐2) = -(8π𝐺/𝑐2)𝜌, [Re (2.99)] we get Friedmann equation [-3/𝑐2 [(𝑎̇/𝑎)2 + 𝑘𝑐2/𝑎2𝑅02] = -(8π𝐺/𝑐2)𝜌, (𝑎̇/𝑎)2 + 𝑘𝑐2/𝑎2𝑅02 = (8π𝐺/𝑐2 𝑐2/3)𝜌]
    (2.136)   (𝑎̇/𝑎)2 = 8π𝐺/3 𝜌 - 𝑘𝑐2/𝑎2𝑅02 ( + 𝛬𝑐2/3),
where 𝜌 should be understood as the sum of all contributions to the energy density of the universe. We will write 𝜌𝑟 for the contribution from radiation (with 𝜌𝛾 for photons and 𝜌𝜈 for neutrinos), 𝜌𝑚 for the contribution by matter (with 𝜌𝑐 for cold dark matter and 𝜌𝑏 for baryons) and 𝜌𝛬 for vacuum energy contribution. Equation (2.136) is the fundamental equation describing the evolution of the scale factor. To write it as a closed form equation for 𝑎(𝑡), we have to specify the evolution of the density, 𝜌(𝑎), as in (2.107), 𝜌 ∝ 𝑎-3(1 + 𝜔).
   The spatial part of the Einstein equation, 𝐺𝑖𝑗 = (8π𝐺/𝑐4)𝛵𝑖𝑗, leads to the second Friedmann equation (also known as the Raychaudhuri equation).
    (2.137)   (𝑑𝑎̇/𝑑𝑡)/𝑎 = -4π𝐺/3 (𝜌 + 3𝑃/𝑐2) ( + 𝛬𝑐2/3)
Derivation   Taking a time derivative of the first equation (2.136) and using the continuity equation (2.106) ῤ = -3𝑎̇/𝑎 (𝜌 + 𝑃/𝑐2),
       𝑑/𝑑𝑡 (𝑎̇/𝑎)2 = 𝑑/𝑑𝑡 (8π𝐺/3 𝜌 - 𝑘𝑐2/𝑎2𝑅02),   2/𝑎3 (𝑎𝑎̇ 𝑑𝑎̇/𝑑𝑡 - 𝑎̇3) = 8π𝐺/3 ῤ - (-2𝑎̇/𝑎3 𝑘𝑐2/𝑅02) = 8π𝐺/3 [-3𝑎̇/𝑎 (𝜌 + 𝑃/𝑐2)] + 2𝑎̇/𝑎3 𝑘𝑐2/𝑅02
       (𝑑𝑎̇/𝑑𝑡)/𝑎 = (𝑎̇/𝑎)2 + 1/2 8π𝐺/3 [-3(𝜌 + 𝑃/𝑐2)] + 𝑘𝑐2/𝑎2𝑅02 = 8π𝐺/3 𝜌 - 𝑘𝑐2/𝑎2𝑅02 + 4π𝐺/3 [-3(𝜌 + 𝑃/𝑐2)] + 𝑘𝑐2/𝑎2𝑅02 = 4π𝐺/3 (𝜌 + 3𝑃/𝑐2). ▮ 

Newtonian derivation   Some intuition for the form of the Friedmann equations can be developed from a non-relativistic Newtonian analysis. Consider an expanding sphere a matter of uniform mass density 𝜌(𝑡) and radius 𝑅(𝑡) = 𝑎(𝑡)𝑅(0). Let us study the dynamics of a test particle on the surface of the sphere. The acceleration of the particle is
    (2.138)   𝑑Ṙ/𝑑𝑡 = 𝐺𝑀(𝑅)/𝑅2,   𝑀(𝑅) = 4μ/3 𝑅3 𝜌,
where 𝑀(𝑅) is the mass enclosed in the ball of radius 𝑅. Multiplying this by 𝑅 and integrating, we get
    (2.139)   1/2 Ṙ2 - 𝐺𝑀(𝑅)/𝑅 = 𝐸
where the integration constant 𝐸 is the energy per unit mass of the particle. In terms of the scale factor and the density, this becomes
    (2.140)   (𝑎̇/𝑎)2 = 8π𝐺/3 𝜌 - 2𝐸/𝑎2𝑅02.
Identifying 2𝐸 with -𝑘𝑐2, this is the form of Friedmann equation for a pressureless fluid. We see that we describe the flatness problem in Chapter 4.

   The first Friedmann equation is often written in terms of Hubble parameter, 𝐻 ≡ 𝑎̇/𝑎,
    (2.141)   𝐻2 = 8π𝐺/3 𝜌 - 𝑘𝑐2/𝑎2𝑅02.
We will use the subscript '0' to denote quantity evaluated today, at 𝑡 = 𝑡0. A flat universe (𝑘 = 0) corresponds to the following critical density today.
    (2.142)   𝜌crit,0 = 3𝐻02/8π𝐺 = 1.9 × 10-29 𝘩2 g cm-3 = 2.8 × 1011 𝘩2 𝛭 Mpc-3 = 1.1 × 10-5 𝘩2 protons cm-3.
It is convenient to measure all densities relative to the critical density and work with following dimensionless density parameters
    (2.143)   𝛺𝑖,0 ≡ 𝜌𝑖,0/𝜌crit,0,   𝑖 = 𝑟, 𝑚, 𝛬, . . .
The density parameter 𝛺𝑖,0 is often dropped so that 𝛺𝑖denotes the density today in terms of the critical density today. We will follow the convention. The Friedman equation (2.141) can be then be written as
    (2.144)   𝐻2/𝐻02 = 𝛺𝑟𝑎-4 + 𝛺𝑚𝑎-3 + 𝛺𝑘𝑎-2 + 𝛺𝛬,
where we introduces the curvature "density" parameter 𝛺𝑘, 𝛺𝑘 ≡ -𝑘𝑐2/(𝑅0𝐻0)2. Note that 𝛺𝑘 < 0 for 𝑘 > 0. Evaluating both sides of the equation at the present time, with 𝑎(𝑡0) ≡ 1, leads to the constraint
    (2.145)   1 = {𝛺𝑟 + 𝛺𝑚 + 𝛺𝛬}(≡𝛺0) + 𝛺𝑘
and the curvature parameter can be written as 𝛺𝑘 = 1 - 𝛺0. An central task in cosmology is to measure the parameters occurring in the Friedmann equation (2.144) and hence determine the composition of the universe. These measurements will be described in Section 2.4.

          2.3.6 Exact Solutions  
   In general, the Friedmann equation is a complicated nonlinear differential equations for the scale factor 𝑎(𝑡). Some special cases from exact solutions are good approximations to the real universe for certain periods of time

          Single-component universes    
Consider first a flat universe (𝑘 = 0) with just a single fluid. In fact, the different scalings of the densities of radiation (𝑎-4), matter (𝑎-3) and vacuum energy (𝑎0) imply that for most of its history, the universe was dominated by a single component (first radiation, then matter, then vacuum energy; see Fig. 2.10). Parameterizing this component by its equation of state, 𝜔 = 𝛲/(𝜌𝑐2) captures all cases of interest. The Friedmann equation (2.144) then reduces to
    (2.146)   [𝐻 = 𝑎̇/𝑎 =] 𝑑(ln 𝑎)/𝑑𝑡 ≈ 𝐻0 √𝛺𝑖 𝑎-3/2 (1+𝜔𝑖).
Derivation  𝛺𝑖 ≡ 𝜌𝑖/𝜌crit, 𝜌 ∝ 𝑎-3(1+𝜔𝑖) [RE (2.107)], From (2.144) 𝐻2/𝐻02 = 𝛺𝑟𝑎-4 + 𝛺𝑚𝑎-3 + 𝛺𝑘𝑎-2 + 𝛺𝛬 ≈ 𝛺𝑖 𝑎-3(1+𝜔𝑖)   ⇒   𝐻 ≈ 𝐻0 √𝛺𝑖 𝑎-3/2 (1+𝜔𝑖).  ▮
Integrating this equation, we obtain the time independence of the scale factor
    (2.147)   𝑎(𝑡) ∝ { 𝑡2/3(1 + 𝜔𝑖)   𝜔𝑖 ≠ -1   𝑡2/3   𝛭𝐷;    𝑡1/2    𝑅𝐷┃𝑒𝐻0√𝛺𝛬 𝑡   𝜔𝑖 = -1   𝐴𝐷,  
where 𝛭𝐷, 𝑅𝐷 and 𝐴𝐷 stand for matter dominated, radiation dominated and dark energy dominated, respectively.
   In conformal time, the Friedmann equation becomes [RE (2.23) 𝑑𝜂 = 𝑑𝑡/𝑎(𝑡), so 𝑑𝑡 = 𝑑𝜂 𝑎(𝑡), 𝑑(ln 𝑎)/𝑑𝑡 = 𝑑(ln 𝑎)/𝑑𝜂 𝑎 ≈ 𝐻0 √𝛺𝑖 𝑎-3/2 (1+𝜔𝑖), therefore, as follows]
    (2.148)   𝑑(ln 𝑎)/𝑑𝜂 ≈ 𝐻0 √𝛺𝑖 𝑎-1/2 (1+3𝜔𝑖),
and we get
    (2.149)   𝑎(𝜂) ∝ { 𝜂2/(1 + 3𝜔𝑖)   𝜔𝑖 ≠ -1   𝜂2   𝛭𝐷;    𝜂    𝑅𝐷┃(-𝜂)-1   𝜔𝑖 = -1   𝐴𝐷,  
which reads 𝜂2, 𝜂 and (-𝜂)-1 for a matter dominated, radiation dominated and dark energy dominated universe, respectively. The special case 𝜔𝑖 = -1/3 corresponds to a universe dominated by spatial curvature.

The solution for a pure matter universe is known as the Einstein-de Sitter universe
    (2.150)   𝑎(𝑡) = (𝑡/𝑡0)2/3.  
The solutions was first derived by Einstein and de Sitter in an influential two page paper. Equation (2.150) imply following relation between Hubble constant, 𝐻0, and  the age of the universe, 𝑡0:   [Time derivative of the both sides of  (2.150)  is: 𝑎̇ = 2/3 1/𝑡0 and 𝐻0 = 𝑎̇(𝑡0)/𝑎(𝑡0), If we set 𝑡 = 𝑡0 and 𝑎(𝑡0 =1, then we have 𝐻0 = 𝑎̇(𝑡0)/𝑎(𝑡0) = 2/3 1/𝑡0 1/𝑎(𝑡0 = 2/3 1/𝑡0.]
    (2.151)   𝐻0 = = 2/3 1/𝑡0
Taking the observed value of the Hubble constant,  𝐻0 ≈ 70 km s-1 -1, then leads to,
    (2.152)   𝑡0 = 2/3 𝐻0-1 ≈ 9 billion yrs.
This is the famous "age problem": the age of a pure matter universe ia shorter than that of the oldest stars.

   The above results also apply to a universe without any matter and only a curvature term. The 𝑎-2 scaling of the curvature contribution implies that we must set 𝜔𝑘 = - 1/3. In the absence of additional fluid contributions, the Friedmann equation then admits a solution for 𝑘 = -1. In the case we get [In (2.136) if 𝜔𝑖 =-1/3, (2.144), 𝐻2/𝐻02 = 𝛺𝑘𝑎-2. 𝛺𝑘 = 𝜌𝑘/𝜌crit. In (2.141) if 𝑘 = -1, then 𝜌𝑘 > 0. In (2.147), if 𝜔𝑖 =-1/3, then 𝑎(𝑡) ∝ 𝑡.]
       (2.153)   𝑎(𝑡) = 𝑡/𝑡0,
which is called the Milne universe.

  The solution for a cosmological constant, 𝜔𝛬 = - 1, is known de Sitter space. This de Sitter solution turns out to be a good approximation to the evolution of our universe in both far past and the far future. For now it seems that  the time dependence in the de Sitter solution in (2.147) is somewhat a fake. All physical quantities-like the density 𝜌-are independent of time in the exact de Sitter space. To have any cosmological evolution requires that this time-translation invariance of de Sitter background is broken by a time-dependent form of stress-energy.

          A Singularity theorem    
With the exception of the de Sitter solution, the solutions above all have a singularity at 𝑡 = 0. In particular, the scale factor goes to zero and the density diverges as 𝜌 ∝ 𝑡2. As famously proven by Hawking and Penrose {RE reference Chapter 2 (12)], this singularity is actually a generic feature of all Big Bang cosmologies.We can get a glimpse of this singularity theorem for the special case of our FRW spacetimes.
   Consider the second Friedmann equation, [RE (2.137)],
    (2.154)   (𝑑𝑎̇/𝑑𝑡)/𝑎 = -4π𝐺/3 (𝜌 + 3𝑃/𝑐2).
We will now show that this implies a singularity in the past, as long as the matter obeys the strong energy condition, 𝜌 + 3𝑃/𝑐2 ≥ 0, so that 𝑑𝑎̇/𝑑𝑡 < 0 at all times. This makes sense gravity attractive for all familiar matter sources, so it shows down the expansion. We want to show that 𝑎(𝑡) must have started from zero at some point in the past. It is easiest to prove this graphically (see Fig. 2.11).
   Let us pick up some fiducial time 𝑡 = 𝑡0 (which may be present time) and specify two conditions on the scale factor at that time
    (2.155)   𝑎(𝑡0) = 1.     𝑎̇(𝑡0) = 𝐻0.   [𝐻 ≡ 𝑎̇/𝑎, 𝐻0 = 𝑎̇(𝑡0)/𝑎(𝑡0) = 𝑎̇(𝑡0).]
We assume that the universe is expanding at 𝑡0, so that 𝐻0 > 0. we use (2.154) to evolve the universe backwards in time. Consider first the special case 𝑑𝑎̇/𝑑𝑡 = 0,. The solution is 𝑎(𝑡) = 1 + 𝐻0(𝑡 - 𝑡0). (see the dashed line in Fig 2.11). Now let us compare the special case 𝑑𝑎̇/𝑑𝑡 = 0 to solution with 𝑑𝑎̇/𝑑𝑡 < 0. It has the same tangent at 𝑡0, but smaller 𝑎(𝑡) at 𝑡 < 𝑡0. The solid line in the figure shows an example. Any solution with 𝑑𝑎̇/𝑑𝑡 < 0, for all  𝑡 < 𝑡0, therefore also has a singularity at some 𝑡𝑖>𝑡0 - 𝐻0-1. [In the figure if 𝑎(𝑡) = 0, then 0 = 1 + 𝐻0(𝑡 - 𝑡0), -𝐻0-1 = 𝑡 - 𝑡0, therefore 𝑡 = 𝑡0 - 𝐻0-1.]
   This singularity theorem assumed the FRW solution. The singularity theorem by Hawking and Penrose is more general, but also much more complicated to prove.

          Two-component universes    
It will also be convenient to have solutions for the case of two fluid components. This is relevant in the early universe of a mixture of matter and radiation, in the late universe, where both matter and dark energy are important.
   We often work in conformal time 𝜂 to obtain a solution for the evolution of a scale factor. We will use primes to denote derivative with respect to 𝜂. Using  𝑎̇ = 𝑎ʹ/𝑎 and 𝑑𝑎̇/𝑑𝑡 = 𝑎ʺ/𝑎2 - (𝑎ʹ)2/𝑎3. the Friedmann equations (2.136) and (2.137) then are [In (2.23) 𝑑𝜂 = 𝑑𝑡/𝑎, we find 𝑎̇ = 𝑑𝑎/𝑑𝑡 = 𝑑𝑎/𝑎𝑑𝜂 = 𝑎ʹ/𝑎 and we can get 𝑑𝑎̇/𝑑𝑡 from taking a time derivative of the both side. ... more ...]
    (2.156)   (𝑎ʹ)2 + 𝑘𝑐2/𝑅02 𝑎2 = 8π𝐺/3 𝜌𝑎4,
    (2.157)   𝑎ʺ + 𝑘𝑐2/𝑅02 𝑎 = 4π𝐺/3 (𝜌 - 3𝑃/𝑐2) 𝑎3.

 Matter and radiation 
Consider a flat universe filled with a mixture of matter and radiation. The total density can be written as
    (2.158)   𝜌 ≡ 𝜌𝑚 + 𝜌𝑟 = 𝜌eq/2 [(𝑎eq/𝑎)3 + (𝑎eq/𝑎)4],
where the subscript 'eq' denotes quantities evaluated at matter-radiation equality. Since 𝜌𝑚𝑎3 =const = 1/2 𝜌𝑚𝑎eq3 and 𝑘 = 0, we can write (2.157) as
    (2.159)   𝑎ʺ = 2π𝐺/3 𝜌eq𝑎eq3.  
This equation has the following solution
    (2.160)   𝑎(𝜂) = π𝐺/3 𝜌eq𝑎eq3 𝜂2 + 𝐶𝜂 + 𝐷,  
where 𝐶 and 𝐷 are integration constants. Using 𝑎(𝜂=0) ≡ 0, we have 𝐷 = 0. Substituting (2.160) into (2.156) then gives
    (2.161)   𝐶 = (4π𝐺/3 𝜌eq𝑎eq4)1/2,
and the solution (2.160) can be written as
    (2.162)   𝑎(𝜂) = 𝑎eq[(𝜂/𝜂*)2  + 2 (𝜂/𝜂*)]
where
    (2.163)   𝜂* ≡ (π𝐺/3 𝜌eq𝑎eq2)-1/2 = 𝜂eq/(√2 - 1).  
For 𝜂 ≪ 𝜂eq, we recover the radiation-dominated limit, 𝑎 ∝ 𝜂, while for 𝜂 ≫ 𝜂eq, we agree with the matter-dominated limit, 𝑎 ∝ 𝜂2.

 Matter and curvature
A historically important solution is universe containing a mixture of matter and spatial curvature. Before the discovery of dark energy, it was believed that pressureless matter would dominate at late times. In that case, the fate of the universe would be determined by its spatial curvature. A positively-curved universe would recollapse and end in Big Crunch, while a negative-curved universe would expand forever. Let us derive these facts.
   Defining the conformal Hubble parameter as 𝓗 ≡ 𝑎ʹ/𝑎, the two Friedman equations (2.156) and (2.157) can be written as  
[Corollary   𝓗 = 𝐻𝑎.     ⇐     𝐻 = 𝑎̇/𝑎,  𝑑𝜂 = 𝑑𝑡/𝑎(𝑡),  𝓗 ≡ 𝑎ʹ/𝑎 = 𝑑𝑎/𝑑𝜂 (𝑑𝜂/𝑑𝑡 𝑑𝑡/𝑑𝜂) 1/𝑎 = 𝐻𝑎. ▮]
    (2.164)   𝓗2 + 𝑘𝑐2/𝑅02 = 8π𝐺/3 𝜌𝑚𝑎2,  
    (2.165)   𝑑𝓗/𝑑𝜂 = 4π𝐺/3 𝜌𝑚𝑎2.  
Combing (2.165) and (2.164) allows us to eliminate the dependence on 𝜌𝑚, and we find
    (2.166)   2 𝑑𝓗/𝑑𝜂 + 𝓗2 + 𝑘𝑐2/𝑅02 = 0.  
introducing the dimensionless time coordinate 𝜃 ≡ 𝑐𝜂/𝑅0 and the rescaled Hubble parameter 𝓗* ≡ 𝑅0𝓗/𝑐, this becomes
    (2.167)   2 𝑑Ȟ/𝑑𝜃 + 𝓗*2 + 𝑘 = 0.  
The solution of this equation are  
    (2.168)   𝓗*(𝜃) = 1/𝑎 𝑑𝑎/𝑑𝜃 = { cot(𝜃/2)   𝑘 = +1,    𝜃/2    𝑘 = 0,    coth(𝜃/2)   𝑘 = -1,
which is easily integrated to give the evolution of the scale factor
    (2.169)   𝑎(𝜃) = 𝛢 { sin2(𝜃/2)   𝑘 = +1,     𝜃2    𝑘 = 0,     sinh2(𝜃/2)   𝑘 = -1,
where 𝛢 is an integration constant. At early times, all solutions scale as 𝜃2 ∝ 𝜂2, as required for a matter-dominated universe. Using the solution for the scale factor, we obtain the following relation between the conformal and physical time coordinates
    (2.170)   𝑡 = 𝑅0/𝑐 𝑎(𝜃) 𝑑𝜃 = 𝑅0𝛢/2𝑐 { 𝜃 - sin(𝜃)   𝑘 = +1,     𝜃3    𝑘 = 0,     sinh(𝜃) - 𝜃   𝑘 = -1.
Equation (2.169) and (2.170) then determine 𝑎(𝑡) in parametric form. A plot of the solutions is shown in Fig. 2.12. as mentioned, a universe with positive curvature recollapse in the future.
   The maximal expansion of the positive-curvature universe can be found from the Friedmann equation
    (2.171)   𝐻2/𝐻02 = 𝛺0/𝑎3 + (1 - 𝛺0)/𝑎2.
At the turn-around point, the expansion rate must vanish, 𝐻(𝑡) = 0, which occurs when
    (2.172)   𝑎max = 𝛺0/(𝛺0 - 1).
This also fixes the integration constant in (2.169) and (2.170) to be 𝛢 = 𝛺0/∣𝛺0 - 1∣. Explaining why our universe lives so close to the boundary separating recollapse and eternal expansion, is called the flatness problem (see Chapter 4).

 Cosmological constant and curvature
Next, we consider a universe with cosmological constant and spatial curvature. The Friedman equation is  
    (2.173)   𝐻2 = 𝛬𝑐3/3 - 𝑘𝑐2/𝑎2𝑅02.
For 𝛬 > 0, this has the following solutions   [verification. needed]
    (2.174)   𝑎(𝑡) = 𝛢 { cosh(𝛼𝑡)   𝑘 = +1,    exp(𝛼𝑡)   𝑘 = 0,     sinh(𝛼𝑡)   𝑘 = -1,
where 𝛼 ≡ √(𝛬𝑐2/3). The normalization 𝛢 equals √(3/𝛬)/𝑅0 for the 𝑘 = ±1 solutions, and is arbitrary for the 𝑘 = 0 solution. These solutions are shown in Fig. 2.13. We see that the 𝑘 = +1 solution doesn't have a singularity, while the scale factor seems to vanish at 𝑡 = -∞ and 𝑡 = 0, for the 𝑘 = 0 and 𝑘 = -1 solutions, respectively. The latter singularities, however, are coordinate artifacts. In fact the three solutions represent different slicings of the same de Sitter space.7
   For 𝛬 < 0, solutions only exist for 𝑘 = -1. The solution of Friedmann equation is
    (2.175)  𝑎(𝑡) = 𝛢 sin(𝛼𝑡),
where  𝛼 ≡ √(-𝛬𝑐2/3). The so called anti-de Sitter space plays an important role as a playground for toy models of quantum gravity [13].

 Matter and cosmological constant
Finally, we look at a flat universe with matter and a positive cosmological constant, which is a good approximation to our universe today. The Friedman equation is
    (2.176)  𝐻2/𝐻02 = 𝛺𝑚/𝑎3 + 𝛺𝛬,
where 𝛺𝑚 + 𝛺𝛬 = 1. This has the following solution
    (2.177)  𝑎(𝑡) = (𝛺𝑚/𝛺𝛬)1/3 sinh2/3 (3/2 𝛼𝑡),  
  where 𝛼 ≡ √𝛺𝛬 𝐻0.
At early times, this solution reduces to 𝑎 ~ 𝑡2/3, as expected for the early matter-dominated period. Similarly, at late times, we recover the scaling of the de Sitter solution in the flat-slicing, 𝑎 ~ exp(𝛼𝑡). Using 𝑎(𝑡0) ≡ 1, we can solve (2.177) for the age of the universe
    (2.178)  𝑡0 = 2/(3√ 𝛺𝛬 𝐻0) sinh-1 [√(𝛺𝛬/𝛺𝑚)].
Derivation   𝐻0𝑡 = 𝑎0 𝑑𝑎/√(𝛺𝑚𝑎-1 + 𝛺𝛬𝑎2) = 𝑎𝑚𝛬3/2/√𝛺𝑚 𝑦0 √𝑦/√(1 + 𝑦3) 𝑑𝑦,   𝑎𝑚𝛬 ≡ (𝛺𝑚/𝛺𝛬)1/3,   𝑦 ≡ 𝑎/𝑎𝑚𝛬
                = 2/3 𝑎𝑚𝛬3/2/√𝛺𝑚 sinh-1(𝑦3/2) = 2/3 (𝛺𝑚/𝛺𝛬)1/2/√𝛺𝑚 sinh-1(𝑎3/2/ (𝛺𝑚/𝛺𝛬)1/2) = 2/3 1/√𝛺𝛬 sinh-1[𝑎3/2 √(𝛺𝛬/𝛺𝑚)]  
          𝑡 = 2/3 1/𝐻0 1/√𝛺𝛬 sinh-1[𝑎3/2 √(𝛺𝛬/𝛺𝑚)] = 2/(3√𝛺𝛬 𝐻0) sinh-1(𝑎3/2 √𝛺𝛬/√𝛺𝑚).   Since 𝑎(𝑡0) = 1, we get
          𝑡0 = 2/(3√ 𝛺𝛬 𝐻0) sinh-1[√(𝛺𝛬/𝛺𝑚)].  ▮
Substituting the observed values of the cosmological parameter (𝛺𝑚 = 0.32 and 𝛺𝛬 = 0.68), we can find
    (2.179)  𝑡0 = 0.95 𝐻0-1 ≈ 0.95 × 14.4 Gyrs ≈ 13.7 Gyrs. [correction: 0.96→0.95, 14→13.7]
Derivation  1/𝐻0 ≈ 1/68 s Mpc/km ≈ 1/68 × 3.0857 × 1019 s ≈ 4.538 × 1017 s ≈ 4.538/3.154 × 1010 years ≈ 14.4 Gyrs.
           2/3 √𝛺𝛬 sinh-1(√𝛺𝛬/√𝛺𝑚) = 2/3 × 1/√0.68 sinh-1(√0.68/√0.32) ≈ 0.95.  ▮
which solves the age problem of the Einstein-de Sitter universe; cf. (2.152).

7 While a matter-dominated universe the spatial curvature is determined by the energy density, for a 𝛬 dominated universe all three types of solutions exist for any given value of 𝜌𝛬. The different solutions therefore describe the same physical spacetime in different coordinates.

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